Get a list (without nested list) directly from a list comprehension [duplicate]
This question already has an answer here:
Interleave multiple lists of the same length in Python
7 answers
I want to return a list with the interleaved elements of two lists directly from the list comprehension - without use a next step to flaten the result. Is it possible?
alist1_temp=[1, 4,2]
alist2_temp=[3, 7,4]
t=[[x,y] for x,y in zip(alist1_temp, alist2_temp)]
Return [[1, 3], [4, 7],[2, 4]]
But how can I get directly from the list-comprehension [1, 3, 4, 7, 2, 4]?
python list list-comprehension
edited 1 hour ago
jonrsharpe
76.8k11102208
asked 1 hour ago
Pedro Pinto
704
marked as duplicate by shash678, ShadowRanger python
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1 hour ago
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
This question already has an answer here:
Interleave multiple lists of the same length in Python
7 answers
I want to return a list with the interleaved elements of two lists directly from the list comprehension - without use a next step to flaten the result. Is it possible?
alist1_temp=[1, 4,2]
alist2_temp=[3, 7,4]
t=[[x,y] for x,y in zip(alist1_temp, alist2_temp)]
Return [[1, 3], [4, 7],[2, 4]]
But how can I get directly from the list-comprehension [1, 3, 4, 7, 2, 4]?
python list list-comprehension
edited 1 hour ago
jonrsharpe
76.8k11102208
asked 1 hour ago
Pedro Pinto
704
marked as duplicate by shash678, ShadowRanger python
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1 hour ago
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
This question already has an answer here:
Interleave multiple lists of the same length in Python
7 answers
I want to return a list with the interleaved elements of two lists directly from the list comprehension - without use a next step to flaten the result. Is it possible?
alist1_temp=[1, 4,2]
alist2_temp=[3, 7,4]
t=[[x,y] for x,y in zip(alist1_temp, alist2_temp)]
Return [[1, 3], [4, 7],[2, 4]]
But how can I get directly from the list-comprehension [1, 3, 4, 7, 2, 4]?
python list list-comprehension
edited 1 hour ago
jonrsharpe
76.8k11102208
asked 1 hour ago
Pedro Pinto
704
This question already has an answer here:
Interleave multiple lists of the same length in Python
7 answers
I want to return a list with the interleaved elements of two lists directly from the list comprehension - without use a next step to flaten the result. Is it possible?
alist1_temp=[1, 4,2]
alist2_temp=[3, 7,4]
t=[[x,y] for x,y in zip(alist1_temp, alist2_temp)]
Return [[1, 3], [4, 7],[2, 4]]
But how can I get directly from the list-comprehension [1, 3, 4, 7, 2, 4]?
This question already has an answer here:
Interleave multiple lists of the same length in Python
7 answers
python list list-comprehension
python list list-comprehension
edited 1 hour ago
jonrsharpe
76.8k11102208
asked 1 hour ago
Pedro Pinto
704
edited 1 hour ago
jonrsharpe
76.8k11102208
asked 1 hour ago
Pedro Pinto
704
edited 1 hour ago
jonrsharpe
76.8k11102208
edited 1 hour ago
jonrsharpe
76.8k11102208
edited 1 hour ago
jonrsharpe
76.8k11102208
76.8k11102208
asked 1 hour ago
Pedro Pinto
704
asked 1 hour ago
Pedro Pinto
704
asked 1 hour ago
Pedro Pinto
704
704
marked as duplicate by shash678, ShadowRanger python
Users with the python badge can single-handedly close python questions as duplicates and reopen them as needed.
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1 hour ago
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3 Answers
3
active
oldest
votes
Try this with just zip to get it in that order that you want:
[i for j in zip(alist1_temp, alist2_temp) for i in j]
if you don't mind the order just do:
alist1_temp + alist2_temp
or get it with itertools.chain thanks to @buran:
import itertools
list(itertools.chain(alist1_temp, alist2_temp))
answered 1 hour ago
Mehrdad Pedramfar
4,78211237
with the chain - why not justlist(itertools.chain(alist1_temp, alist2_temp))? it's not comprehension, but I am not sure comprehension is strict requirement. And anyway the order of elements in the result is different.
– buran
1 hour ago
@buran Right, surely you are right
– Mehrdad Pedramfar
1 hour ago
@buran Edited, thanks for your comment
– Mehrdad Pedramfar
1 hour ago
add a comment |
If you like numpy way of doing this, you could use this!
np.vstack((alist1_temp,alist2_temp)).flatten('F')
or you can flatten your list comprehension as well
np.array(t).flatten()
answered 1 hour ago
AI_Learning
2,4691628
add a comment |
As you specified that you want get it from from the list-comprehension:
alist1_temp=[1,4,2]
alist2_temp=[3,7,4]
L = len(alist1_temp)+len(alist2_temp)
t = [alist2_temp[i//2] if i%2 else alist1_temp[i//2] for i in range(L)]
print(t) #prints [1, 3, 4, 7, 2, 4]
answered 1 hour ago
Daweo
1562
add a comment |
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Try this with just zip to get it in that order that you want:
[i for j in zip(alist1_temp, alist2_temp) for i in j]
if you don't mind the order just do:
alist1_temp + alist2_temp
or get it with itertools.chain thanks to @buran:
import itertools
list(itertools.chain(alist1_temp, alist2_temp))
answered 1 hour ago
Mehrdad Pedramfar
4,78211237
with the chain - why not justlist(itertools.chain(alist1_temp, alist2_temp))? it's not comprehension, but I am not sure comprehension is strict requirement. And anyway the order of elements in the result is different.
– buran
1 hour ago
@buran Right, surely you are right
– Mehrdad Pedramfar
1 hour ago
@buran Edited, thanks for your comment
– Mehrdad Pedramfar
1 hour ago
add a comment |
Try this with just zip to get it in that order that you want:
[i for j in zip(alist1_temp, alist2_temp) for i in j]
if you don't mind the order just do:
alist1_temp + alist2_temp
or get it with itertools.chain thanks to @buran:
import itertools
list(itertools.chain(alist1_temp, alist2_temp))
answered 1 hour ago
Mehrdad Pedramfar
4,78211237
with the chain - why not justlist(itertools.chain(alist1_temp, alist2_temp))? it's not comprehension, but I am not sure comprehension is strict requirement. And anyway the order of elements in the result is different.
– buran
1 hour ago
@buran Right, surely you are right
– Mehrdad Pedramfar
1 hour ago
@buran Edited, thanks for your comment
– Mehrdad Pedramfar
1 hour ago
add a comment |
Try this with just zip to get it in that order that you want:
[i for j in zip(alist1_temp, alist2_temp) for i in j]
if you don't mind the order just do:
alist1_temp + alist2_temp
or get it with itertools.chain thanks to @buran:
import itertools
list(itertools.chain(alist1_temp, alist2_temp))
answered 1 hour ago
Mehrdad Pedramfar
4,78211237
Try this with just zip to get it in that order that you want:
[i for j in zip(alist1_temp, alist2_temp) for i in j]
if you don't mind the order just do:
alist1_temp + alist2_temp
or get it with itertools.chain thanks to @buran:
import itertools
list(itertools.chain(alist1_temp, alist2_temp))
answered 1 hour ago
Mehrdad Pedramfar
4,78211237
edited 1 hour ago
answered 1 hour ago
Mehrdad Pedramfar
4,78211237
answered 1 hour ago
Mehrdad Pedramfar
4,78211237
answered 1 hour ago
Mehrdad Pedramfar
4,78211237
4,78211237
with the chain - why not justlist(itertools.chain(alist1_temp, alist2_temp))? it's not comprehension, but I am not sure comprehension is strict requirement. And anyway the order of elements in the result is different.
– buran
1 hour ago
@buran Right, surely you are right
– Mehrdad Pedramfar
1 hour ago
@buran Edited, thanks for your comment
– Mehrdad Pedramfar
1 hour ago
add a comment |
with the chain - why not justlist(itertools.chain(alist1_temp, alist2_temp))? it's not comprehension, but I am not sure comprehension is strict requirement. And anyway the order of elements in the result is different.
– buran
1 hour ago
@buran Right, surely you are right
– Mehrdad Pedramfar
1 hour ago
@buran Edited, thanks for your comment
– Mehrdad Pedramfar
1 hour ago
with the chain - why not just
list(itertools.chain(alist1_temp, alist2_temp))? it's not comprehension, but I am not sure comprehension is strict requirement. And anyway the order of elements in the result is different.– buran
1 hour ago
with the chain - why not just
list(itertools.chain(alist1_temp, alist2_temp))? it's not comprehension, but I am not sure comprehension is strict requirement. And anyway the order of elements in the result is different.– buran
1 hour ago
@buran Right, surely you are right
– Mehrdad Pedramfar
1 hour ago
@buran Right, surely you are right
– Mehrdad Pedramfar
1 hour ago
@buran Edited, thanks for your comment
– Mehrdad Pedramfar
1 hour ago
@buran Edited, thanks for your comment
– Mehrdad Pedramfar
1 hour ago
add a comment |
If you like numpy way of doing this, you could use this!
np.vstack((alist1_temp,alist2_temp)).flatten('F')
or you can flatten your list comprehension as well
np.array(t).flatten()
answered 1 hour ago
AI_Learning
2,4691628
add a comment |
If you like numpy way of doing this, you could use this!
np.vstack((alist1_temp,alist2_temp)).flatten('F')
or you can flatten your list comprehension as well
np.array(t).flatten()
answered 1 hour ago
AI_Learning
2,4691628
add a comment |
If you like numpy way of doing this, you could use this!
np.vstack((alist1_temp,alist2_temp)).flatten('F')
or you can flatten your list comprehension as well
np.array(t).flatten()
answered 1 hour ago
AI_Learning
2,4691628
If you like numpy way of doing this, you could use this!
np.vstack((alist1_temp,alist2_temp)).flatten('F')
or you can flatten your list comprehension as well
np.array(t).flatten()
answered 1 hour ago
AI_Learning
2,4691628
answered 1 hour ago
AI_Learning
2,4691628
answered 1 hour ago
AI_Learning
2,4691628
answered 1 hour ago
AI_Learning
2,4691628
2,4691628
add a comment |
add a comment |
As you specified that you want get it from from the list-comprehension:
alist1_temp=[1,4,2]
alist2_temp=[3,7,4]
L = len(alist1_temp)+len(alist2_temp)
t = [alist2_temp[i//2] if i%2 else alist1_temp[i//2] for i in range(L)]
print(t) #prints [1, 3, 4, 7, 2, 4]
answered 1 hour ago
Daweo
1562
add a comment |
As you specified that you want get it from from the list-comprehension:
alist1_temp=[1,4,2]
alist2_temp=[3,7,4]
L = len(alist1_temp)+len(alist2_temp)
t = [alist2_temp[i//2] if i%2 else alist1_temp[i//2] for i in range(L)]
print(t) #prints [1, 3, 4, 7, 2, 4]
answered 1 hour ago
Daweo
1562
add a comment |
As you specified that you want get it from from the list-comprehension:
alist1_temp=[1,4,2]
alist2_temp=[3,7,4]
L = len(alist1_temp)+len(alist2_temp)
t = [alist2_temp[i//2] if i%2 else alist1_temp[i//2] for i in range(L)]
print(t) #prints [1, 3, 4, 7, 2, 4]
answered 1 hour ago
Daweo
1562
As you specified that you want get it from from the list-comprehension:
alist1_temp=[1,4,2]
alist2_temp=[3,7,4]
L = len(alist1_temp)+len(alist2_temp)
t = [alist2_temp[i//2] if i%2 else alist1_temp[i//2] for i in range(L)]
print(t) #prints [1, 3, 4, 7, 2, 4]
answered 1 hour ago
Daweo
1562
answered 1 hour ago
Daweo
1562
answered 1 hour ago
Daweo
1562
answered 1 hour ago
Daweo
1562
1562
add a comment |
add a comment |
