Starting tasks inside another task is duplicating my WebRequests
I use the code below to check some pdf files online and return a string accordingly.
The problem is: When I added the second Task.Factory.StartNew()
it started duplicating all requests, but still returning only one answer(as it should be).
I need this to be as fast as possible so I can't waste time sending two requests to the server.
public static void Main(string args)
{
var listT = new List<string>()
{
"24006025062"
};
var task = listT.Select(x => Task.Factory.StartNew(() => TesteTask(x)));
Task.WaitAll(task.ToArray(), TimeSpan.FromSeconds(120));
List<string> results = new List<string>();
foreach (var result in task)
{
results.Add(result.Result);
}
}
private static string TesteTask(string codCart)
{
var teste = new Consulta();
var retorno = string.Empty;
var session = teste.GetCaptcha();
for (int i = 0; i < 10; i++)
{
session.CaptchaResolvida = QuebraCaptcha(session.CaptchaCodificada).CaptchaResolvida;
if (session.CaptchaResolvida.Length > 0)
{
var links = teste.Consulta(codCart, session).Retorno;
if (links.Any())
{
var tasks = links.Select(x => Task.Factory.StartNew(() => Executa(teste, session, x)));
Task.WaitAll(tasks.ToArray(), TimeSpan.FromSeconds(120));
var modelList = from Result in tasks select Result.Result;
retorno = teste.FinalizaProcesso(modelList.ToList());
break;
}
}
}
return retorno;
}
private static string Executa(Consulta teste, Model<Request> session, string link)
{
var retorno = string.Empty;
for (int i = 0; i < 10; i++)
{
var CaptchaResolvida = QuebraCaptcha(teste.GetCaptchaPdf(session)).CaptchaResolvida;
if (CaptchaResolvida != null && CaptchaResolvida != string.Empty)
{
var status = teste.BaixaPdf(link, CaptchaResolvida, session);
if (status != string.Empty)
{
retorno = status;
break;
}
}
}
return retorno;
}
Ps: This is my first post on stack overflow, if I'm not clear enough please let me know!
c# multithreading task factory multitasking
add a comment |
I use the code below to check some pdf files online and return a string accordingly.
The problem is: When I added the second Task.Factory.StartNew()
it started duplicating all requests, but still returning only one answer(as it should be).
I need this to be as fast as possible so I can't waste time sending two requests to the server.
public static void Main(string args)
{
var listT = new List<string>()
{
"24006025062"
};
var task = listT.Select(x => Task.Factory.StartNew(() => TesteTask(x)));
Task.WaitAll(task.ToArray(), TimeSpan.FromSeconds(120));
List<string> results = new List<string>();
foreach (var result in task)
{
results.Add(result.Result);
}
}
private static string TesteTask(string codCart)
{
var teste = new Consulta();
var retorno = string.Empty;
var session = teste.GetCaptcha();
for (int i = 0; i < 10; i++)
{
session.CaptchaResolvida = QuebraCaptcha(session.CaptchaCodificada).CaptchaResolvida;
if (session.CaptchaResolvida.Length > 0)
{
var links = teste.Consulta(codCart, session).Retorno;
if (links.Any())
{
var tasks = links.Select(x => Task.Factory.StartNew(() => Executa(teste, session, x)));
Task.WaitAll(tasks.ToArray(), TimeSpan.FromSeconds(120));
var modelList = from Result in tasks select Result.Result;
retorno = teste.FinalizaProcesso(modelList.ToList());
break;
}
}
}
return retorno;
}
private static string Executa(Consulta teste, Model<Request> session, string link)
{
var retorno = string.Empty;
for (int i = 0; i < 10; i++)
{
var CaptchaResolvida = QuebraCaptcha(teste.GetCaptchaPdf(session)).CaptchaResolvida;
if (CaptchaResolvida != null && CaptchaResolvida != string.Empty)
{
var status = teste.BaixaPdf(link, CaptchaResolvida, session);
if (status != string.Empty)
{
retorno = status;
break;
}
}
}
return retorno;
}
Ps: This is my first post on stack overflow, if I'm not clear enough please let me know!
c# multithreading task factory multitasking
add a comment |
I use the code below to check some pdf files online and return a string accordingly.
The problem is: When I added the second Task.Factory.StartNew()
it started duplicating all requests, but still returning only one answer(as it should be).
I need this to be as fast as possible so I can't waste time sending two requests to the server.
public static void Main(string args)
{
var listT = new List<string>()
{
"24006025062"
};
var task = listT.Select(x => Task.Factory.StartNew(() => TesteTask(x)));
Task.WaitAll(task.ToArray(), TimeSpan.FromSeconds(120));
List<string> results = new List<string>();
foreach (var result in task)
{
results.Add(result.Result);
}
}
private static string TesteTask(string codCart)
{
var teste = new Consulta();
var retorno = string.Empty;
var session = teste.GetCaptcha();
for (int i = 0; i < 10; i++)
{
session.CaptchaResolvida = QuebraCaptcha(session.CaptchaCodificada).CaptchaResolvida;
if (session.CaptchaResolvida.Length > 0)
{
var links = teste.Consulta(codCart, session).Retorno;
if (links.Any())
{
var tasks = links.Select(x => Task.Factory.StartNew(() => Executa(teste, session, x)));
Task.WaitAll(tasks.ToArray(), TimeSpan.FromSeconds(120));
var modelList = from Result in tasks select Result.Result;
retorno = teste.FinalizaProcesso(modelList.ToList());
break;
}
}
}
return retorno;
}
private static string Executa(Consulta teste, Model<Request> session, string link)
{
var retorno = string.Empty;
for (int i = 0; i < 10; i++)
{
var CaptchaResolvida = QuebraCaptcha(teste.GetCaptchaPdf(session)).CaptchaResolvida;
if (CaptchaResolvida != null && CaptchaResolvida != string.Empty)
{
var status = teste.BaixaPdf(link, CaptchaResolvida, session);
if (status != string.Empty)
{
retorno = status;
break;
}
}
}
return retorno;
}
Ps: This is my first post on stack overflow, if I'm not clear enough please let me know!
c# multithreading task factory multitasking
I use the code below to check some pdf files online and return a string accordingly.
The problem is: When I added the second Task.Factory.StartNew()
it started duplicating all requests, but still returning only one answer(as it should be).
I need this to be as fast as possible so I can't waste time sending two requests to the server.
public static void Main(string args)
{
var listT = new List<string>()
{
"24006025062"
};
var task = listT.Select(x => Task.Factory.StartNew(() => TesteTask(x)));
Task.WaitAll(task.ToArray(), TimeSpan.FromSeconds(120));
List<string> results = new List<string>();
foreach (var result in task)
{
results.Add(result.Result);
}
}
private static string TesteTask(string codCart)
{
var teste = new Consulta();
var retorno = string.Empty;
var session = teste.GetCaptcha();
for (int i = 0; i < 10; i++)
{
session.CaptchaResolvida = QuebraCaptcha(session.CaptchaCodificada).CaptchaResolvida;
if (session.CaptchaResolvida.Length > 0)
{
var links = teste.Consulta(codCart, session).Retorno;
if (links.Any())
{
var tasks = links.Select(x => Task.Factory.StartNew(() => Executa(teste, session, x)));
Task.WaitAll(tasks.ToArray(), TimeSpan.FromSeconds(120));
var modelList = from Result in tasks select Result.Result;
retorno = teste.FinalizaProcesso(modelList.ToList());
break;
}
}
}
return retorno;
}
private static string Executa(Consulta teste, Model<Request> session, string link)
{
var retorno = string.Empty;
for (int i = 0; i < 10; i++)
{
var CaptchaResolvida = QuebraCaptcha(teste.GetCaptchaPdf(session)).CaptchaResolvida;
if (CaptchaResolvida != null && CaptchaResolvida != string.Empty)
{
var status = teste.BaixaPdf(link, CaptchaResolvida, session);
if (status != string.Empty)
{
retorno = status;
break;
}
}
}
return retorno;
}
Ps: This is my first post on stack overflow, if I'm not clear enough please let me know!
c# multithreading task factory multitasking
c# multithreading task factory multitasking
asked Nov 22 at 18:39
Carlos Alexandre Verísimo
132
132
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You are getting this behavior because you are iterating twice on the Select
returned IEnumerable. Try this:
public static void Main(string args)
{
var listT = new List<string>()
{
"24006025062"
};
var task = list
.Select(x => Task.Factory.StartNew(() => TesteTask(x)))
.ToArray();
Task.WaitAll(task, TimeSpan.FromSeconds(120));
List<string> results = new List<string>();
foreach (var result in task)
{
results.Add(result.Result);
}
}
By moving the ToArray()
just after the Select()
it creates the results IEnumerable only once instead of twice.
Hope it helps!
Thanks, didn't know that.
– Carlos Alexandre Verísimo
Nov 22 at 19:08
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You are getting this behavior because you are iterating twice on the Select
returned IEnumerable. Try this:
public static void Main(string args)
{
var listT = new List<string>()
{
"24006025062"
};
var task = list
.Select(x => Task.Factory.StartNew(() => TesteTask(x)))
.ToArray();
Task.WaitAll(task, TimeSpan.FromSeconds(120));
List<string> results = new List<string>();
foreach (var result in task)
{
results.Add(result.Result);
}
}
By moving the ToArray()
just after the Select()
it creates the results IEnumerable only once instead of twice.
Hope it helps!
Thanks, didn't know that.
– Carlos Alexandre Verísimo
Nov 22 at 19:08
add a comment |
You are getting this behavior because you are iterating twice on the Select
returned IEnumerable. Try this:
public static void Main(string args)
{
var listT = new List<string>()
{
"24006025062"
};
var task = list
.Select(x => Task.Factory.StartNew(() => TesteTask(x)))
.ToArray();
Task.WaitAll(task, TimeSpan.FromSeconds(120));
List<string> results = new List<string>();
foreach (var result in task)
{
results.Add(result.Result);
}
}
By moving the ToArray()
just after the Select()
it creates the results IEnumerable only once instead of twice.
Hope it helps!
Thanks, didn't know that.
– Carlos Alexandre Verísimo
Nov 22 at 19:08
add a comment |
You are getting this behavior because you are iterating twice on the Select
returned IEnumerable. Try this:
public static void Main(string args)
{
var listT = new List<string>()
{
"24006025062"
};
var task = list
.Select(x => Task.Factory.StartNew(() => TesteTask(x)))
.ToArray();
Task.WaitAll(task, TimeSpan.FromSeconds(120));
List<string> results = new List<string>();
foreach (var result in task)
{
results.Add(result.Result);
}
}
By moving the ToArray()
just after the Select()
it creates the results IEnumerable only once instead of twice.
Hope it helps!
You are getting this behavior because you are iterating twice on the Select
returned IEnumerable. Try this:
public static void Main(string args)
{
var listT = new List<string>()
{
"24006025062"
};
var task = list
.Select(x => Task.Factory.StartNew(() => TesteTask(x)))
.ToArray();
Task.WaitAll(task, TimeSpan.FromSeconds(120));
List<string> results = new List<string>();
foreach (var result in task)
{
results.Add(result.Result);
}
}
By moving the ToArray()
just after the Select()
it creates the results IEnumerable only once instead of twice.
Hope it helps!
answered Nov 22 at 18:49
Itay Podhajcer
1,574312
1,574312
Thanks, didn't know that.
– Carlos Alexandre Verísimo
Nov 22 at 19:08
add a comment |
Thanks, didn't know that.
– Carlos Alexandre Verísimo
Nov 22 at 19:08
Thanks, didn't know that.
– Carlos Alexandre Verísimo
Nov 22 at 19:08
Thanks, didn't know that.
– Carlos Alexandre Verísimo
Nov 22 at 19:08
add a comment |
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