How can i convert my python dictionary to below format












0














my dictionary:



[
{
"male_Unmarried": 792,
"male_Husband": 13192,
"male_own_child": 2823,
"male_not_in_family": 4430,
"male_wife": 2,
}
]


expecting:



    [
{
"label": "male_Unmarried",
"value": 792
},
{
"label": "male_Husband",
"value": 13192
},
{
"label": "male_own_child",
"value": 2823
},
{
"label": "male_not_in_family",
"value": 4430
},
{
"label": "male_wife",
"value": 2
}
]


how can i convert first dictionay like second one.



I want for each dictionay of first one
the key will be label and value will be value of first dictonary.



Please have a look










share|improve this question






















  • Do you actually want to JSON-ize it?
    – user2722968
    Nov 22 at 18:37
















0














my dictionary:



[
{
"male_Unmarried": 792,
"male_Husband": 13192,
"male_own_child": 2823,
"male_not_in_family": 4430,
"male_wife": 2,
}
]


expecting:



    [
{
"label": "male_Unmarried",
"value": 792
},
{
"label": "male_Husband",
"value": 13192
},
{
"label": "male_own_child",
"value": 2823
},
{
"label": "male_not_in_family",
"value": 4430
},
{
"label": "male_wife",
"value": 2
}
]


how can i convert first dictionay like second one.



I want for each dictionay of first one
the key will be label and value will be value of first dictonary.



Please have a look










share|improve this question






















  • Do you actually want to JSON-ize it?
    – user2722968
    Nov 22 at 18:37














0












0








0







my dictionary:



[
{
"male_Unmarried": 792,
"male_Husband": 13192,
"male_own_child": 2823,
"male_not_in_family": 4430,
"male_wife": 2,
}
]


expecting:



    [
{
"label": "male_Unmarried",
"value": 792
},
{
"label": "male_Husband",
"value": 13192
},
{
"label": "male_own_child",
"value": 2823
},
{
"label": "male_not_in_family",
"value": 4430
},
{
"label": "male_wife",
"value": 2
}
]


how can i convert first dictionay like second one.



I want for each dictionay of first one
the key will be label and value will be value of first dictonary.



Please have a look










share|improve this question













my dictionary:



[
{
"male_Unmarried": 792,
"male_Husband": 13192,
"male_own_child": 2823,
"male_not_in_family": 4430,
"male_wife": 2,
}
]


expecting:



    [
{
"label": "male_Unmarried",
"value": 792
},
{
"label": "male_Husband",
"value": 13192
},
{
"label": "male_own_child",
"value": 2823
},
{
"label": "male_not_in_family",
"value": 4430
},
{
"label": "male_wife",
"value": 2
}
]


how can i convert first dictionay like second one.



I want for each dictionay of first one
the key will be label and value will be value of first dictonary.



Please have a look







python






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 22 at 18:35









soubhagya

597




597












  • Do you actually want to JSON-ize it?
    – user2722968
    Nov 22 at 18:37


















  • Do you actually want to JSON-ize it?
    – user2722968
    Nov 22 at 18:37
















Do you actually want to JSON-ize it?
– user2722968
Nov 22 at 18:37




Do you actually want to JSON-ize it?
– user2722968
Nov 22 at 18:37












2 Answers
2






active

oldest

votes


















3














You could use a list-comprehension:



lst = [
{
"male_Unmarried": 792,
"male_Husband": 13192,
"male_own_child": 2823,
"male_not_in_family": 4430,
"male_wife": 2,
}
]

print([{'label': k, 'value': v} for k, v in lst[0].items()])

# [{'label': 'male_Unmarried', 'value': 792},
# {'label': 'male_Husband', 'value': 13192},
# {'label': 'male_own_child', 'value': 2823},
# {'label': 'male_not_in_family', 'value': 4430},
# {'label': 'male_wife', 'value': 2}]





share|improve this answer





























    1














    lst=[ {"male_Unmarried": 792,"male_Husband": 13192,"male_own_child": 2823,
    "male_not_in_family": 4430,"male_wife": 2,} ]
    lst_new = [{"label":i,"value":a[0][i]} for i in lst[0]]
    lst_new
    [{'label': 'male_Unmarried', 'value': 792},
    {'label': 'male_wife', 'value': 2},
    {'label': 'male_own_child', 'value': 2823},
    {'label': 'male_not_in_family', 'value': 4430},
    {'label': 'male_Husband', 'value': 13192}]





    share|improve this answer























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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      3














      You could use a list-comprehension:



      lst = [
      {
      "male_Unmarried": 792,
      "male_Husband": 13192,
      "male_own_child": 2823,
      "male_not_in_family": 4430,
      "male_wife": 2,
      }
      ]

      print([{'label': k, 'value': v} for k, v in lst[0].items()])

      # [{'label': 'male_Unmarried', 'value': 792},
      # {'label': 'male_Husband', 'value': 13192},
      # {'label': 'male_own_child', 'value': 2823},
      # {'label': 'male_not_in_family', 'value': 4430},
      # {'label': 'male_wife', 'value': 2}]





      share|improve this answer


























        3














        You could use a list-comprehension:



        lst = [
        {
        "male_Unmarried": 792,
        "male_Husband": 13192,
        "male_own_child": 2823,
        "male_not_in_family": 4430,
        "male_wife": 2,
        }
        ]

        print([{'label': k, 'value': v} for k, v in lst[0].items()])

        # [{'label': 'male_Unmarried', 'value': 792},
        # {'label': 'male_Husband', 'value': 13192},
        # {'label': 'male_own_child', 'value': 2823},
        # {'label': 'male_not_in_family', 'value': 4430},
        # {'label': 'male_wife', 'value': 2}]





        share|improve this answer
























          3












          3








          3






          You could use a list-comprehension:



          lst = [
          {
          "male_Unmarried": 792,
          "male_Husband": 13192,
          "male_own_child": 2823,
          "male_not_in_family": 4430,
          "male_wife": 2,
          }
          ]

          print([{'label': k, 'value': v} for k, v in lst[0].items()])

          # [{'label': 'male_Unmarried', 'value': 792},
          # {'label': 'male_Husband', 'value': 13192},
          # {'label': 'male_own_child', 'value': 2823},
          # {'label': 'male_not_in_family', 'value': 4430},
          # {'label': 'male_wife', 'value': 2}]





          share|improve this answer












          You could use a list-comprehension:



          lst = [
          {
          "male_Unmarried": 792,
          "male_Husband": 13192,
          "male_own_child": 2823,
          "male_not_in_family": 4430,
          "male_wife": 2,
          }
          ]

          print([{'label': k, 'value': v} for k, v in lst[0].items()])

          # [{'label': 'male_Unmarried', 'value': 792},
          # {'label': 'male_Husband', 'value': 13192},
          # {'label': 'male_own_child', 'value': 2823},
          # {'label': 'male_not_in_family', 'value': 4430},
          # {'label': 'male_wife', 'value': 2}]






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 22 at 18:38









          Austin

          9,4023828




          9,4023828

























              1














              lst=[ {"male_Unmarried": 792,"male_Husband": 13192,"male_own_child": 2823,
              "male_not_in_family": 4430,"male_wife": 2,} ]
              lst_new = [{"label":i,"value":a[0][i]} for i in lst[0]]
              lst_new
              [{'label': 'male_Unmarried', 'value': 792},
              {'label': 'male_wife', 'value': 2},
              {'label': 'male_own_child', 'value': 2823},
              {'label': 'male_not_in_family', 'value': 4430},
              {'label': 'male_Husband', 'value': 13192}]





              share|improve this answer




























                1














                lst=[ {"male_Unmarried": 792,"male_Husband": 13192,"male_own_child": 2823,
                "male_not_in_family": 4430,"male_wife": 2,} ]
                lst_new = [{"label":i,"value":a[0][i]} for i in lst[0]]
                lst_new
                [{'label': 'male_Unmarried', 'value': 792},
                {'label': 'male_wife', 'value': 2},
                {'label': 'male_own_child', 'value': 2823},
                {'label': 'male_not_in_family', 'value': 4430},
                {'label': 'male_Husband', 'value': 13192}]





                share|improve this answer


























                  1












                  1








                  1






                  lst=[ {"male_Unmarried": 792,"male_Husband": 13192,"male_own_child": 2823,
                  "male_not_in_family": 4430,"male_wife": 2,} ]
                  lst_new = [{"label":i,"value":a[0][i]} for i in lst[0]]
                  lst_new
                  [{'label': 'male_Unmarried', 'value': 792},
                  {'label': 'male_wife', 'value': 2},
                  {'label': 'male_own_child', 'value': 2823},
                  {'label': 'male_not_in_family', 'value': 4430},
                  {'label': 'male_Husband', 'value': 13192}]





                  share|improve this answer














                  lst=[ {"male_Unmarried": 792,"male_Husband": 13192,"male_own_child": 2823,
                  "male_not_in_family": 4430,"male_wife": 2,} ]
                  lst_new = [{"label":i,"value":a[0][i]} for i in lst[0]]
                  lst_new
                  [{'label': 'male_Unmarried', 'value': 792},
                  {'label': 'male_wife', 'value': 2},
                  {'label': 'male_own_child', 'value': 2823},
                  {'label': 'male_not_in_family', 'value': 4430},
                  {'label': 'male_Husband', 'value': 13192}]






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Nov 22 at 18:58

























                  answered Nov 22 at 18:53









                  cph_sto

                  1,113219




                  1,113219






























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