Use hexadecimal color as string in darken function











up vote
2
down vote

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In a less style, I have a variable that is a string.



@colorString: 'DADADA';


I can turn it into a color:



@color: ~'#@{colorString}';


I can use @color to set some value from a style:



div { color: @color }


but I cannot use it with the darken() function (or any other built-in function that manages colors).
Example:



background: linear-gradient(to bottom right,darken( @color , 20%), @color);


The compiler outputs
error evaluating function darken: color.toHSL is not a function



it seems that the @color is not a color (#DADADA) but rather is a string ('#DADADA') and the function can't parse it.



Any idea to solve this, without changing the @colorString (it mus be a string)?






css less







share|improve this question


























    up vote
    2
    down vote

    favorite












    In a less style, I have a variable that is a string.



    @colorString: 'DADADA';


    I can turn it into a color:



    @color: ~'#@{colorString}';


    I can use @color to set some value from a style:



    div { color: @color }


    but I cannot use it with the darken() function (or any other built-in function that manages colors).
    Example:



    background: linear-gradient(to bottom right,darken( @color , 20%), @color);


    The compiler outputs
    error evaluating function darken: color.toHSL is not a function



    it seems that the @color is not a color (#DADADA) but rather is a string ('#DADADA') and the function can't parse it.



    Any idea to solve this, without changing the @colorString (it mus be a string)?






    css less







    share|improve this question
























      up vote
      2
      down vote

      favorite









      up vote
      2
      down vote

      favorite











      In a less style, I have a variable that is a string.



      @colorString: 'DADADA';


      I can turn it into a color:



      @color: ~'#@{colorString}';


      I can use @color to set some value from a style:



      div { color: @color }


      but I cannot use it with the darken() function (or any other built-in function that manages colors).
      Example:



      background: linear-gradient(to bottom right,darken( @color , 20%), @color);


      The compiler outputs
      error evaluating function darken: color.toHSL is not a function



      it seems that the @color is not a color (#DADADA) but rather is a string ('#DADADA') and the function can't parse it.



      Any idea to solve this, without changing the @colorString (it mus be a string)?






      css less







      share|improve this question













      In a less style, I have a variable that is a string.



      @colorString: 'DADADA';


      I can turn it into a color:



      @color: ~'#@{colorString}';


      I can use @color to set some value from a style:



      div { color: @color }


      but I cannot use it with the darken() function (or any other built-in function that manages colors).
      Example:



      background: linear-gradient(to bottom right,darken( @color , 20%), @color);


      The compiler outputs
      error evaluating function darken: color.toHSL is not a function



      it seems that the @color is not a color (#DADADA) but rather is a string ('#DADADA') and the function can't parse it.



      Any idea to solve this, without changing the @colorString (it mus be a string)?






      css less




      css less






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 22 at 17:03









      Christian Benseler

      4,78652243




      4,78652243
























          1 Answer
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          up vote
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          down vote



          accepted










          You need to parse the the string to color using color(). 



          @colorString: 'DADADA';
          
@color: color('#@{colorString}');
          
background: linear-gradient(to bottom right, darken(@color, 20%), @color);


          Docs: http://lesscss.org/functions/#misc-functions-color






          share|improve this answer

















          • 1




            I think this is the problem. I tried in my application, which uses 3.7.1 and the color() worked! Thanks!
            – Christian Benseler
            Nov 22 at 17:44











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          1 Answer
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          oldest

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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

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          active

          oldest

          votes








          up vote
          2
          down vote



          accepted










          You need to parse the the string to color using color(). 



          @colorString: 'DADADA';
          
@color: color('#@{colorString}');
          
background: linear-gradient(to bottom right, darken(@color, 20%), @color);


          Docs: http://lesscss.org/functions/#misc-functions-color






          share|improve this answer

















          • 1




            I think this is the problem. I tried in my application, which uses 3.7.1 and the color() worked! Thanks!
            – Christian Benseler
            Nov 22 at 17:44















          up vote
          2
          down vote



          accepted










          You need to parse the the string to color using color(). 



          @colorString: 'DADADA';
          
@color: color('#@{colorString}');
          
background: linear-gradient(to bottom right, darken(@color, 20%), @color);


          Docs: http://lesscss.org/functions/#misc-functions-color






          share|improve this answer

















          • 1




            I think this is the problem. I tried in my application, which uses 3.7.1 and the color() worked! Thanks!
            – Christian Benseler
            Nov 22 at 17:44













          up vote
          2
          down vote



          accepted







          up vote
          2
          down vote



          accepted






          You need to parse the the string to color using color(). 



          @colorString: 'DADADA';
          
@color: color('#@{colorString}');
          
background: linear-gradient(to bottom right, darken(@color, 20%), @color);


          Docs: http://lesscss.org/functions/#misc-functions-color






          share|improve this answer












          You need to parse the the string to color using color(). 



          @colorString: 'DADADA';
          
@color: color('#@{colorString}');
          
background: linear-gradient(to bottom right, darken(@color, 20%), @color);


          Docs: http://lesscss.org/functions/#misc-functions-color







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 22 at 17:27









          The.Bear

          3,15811124




          3,15811124








          • 1




            I think this is the problem. I tried in my application, which uses 3.7.1 and the color() worked! Thanks!
            – Christian Benseler
            Nov 22 at 17:44














          • 1




            I think this is the problem. I tried in my application, which uses 3.7.1 and the color() worked! Thanks!
            – Christian Benseler
            Nov 22 at 17:44








          1




          1




          I think this is the problem. I tried in my application, which uses 3.7.1 and the color() worked! Thanks!
          – Christian Benseler
          Nov 22 at 17:44




          I think this is the problem. I tried in my application, which uses 3.7.1 and the color() worked! Thanks!
          – Christian Benseler
          Nov 22 at 17:44


















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