Setting flag column depending on whether column contains a given string
up vote
7
down vote
favorite
Can anyone see why this isn't working?
Its trying to do; if Column Name Contains the text 'Andy', then make a column called Andy and set that row = to 1
df.loc[df['Name'].str.contains(['Andy']),'Andy']=1
python string pandas series
edited 50 mins ago
jpp
88.1k195099
asked 1 hour ago
fred.schwartz
2597
add a comment |
up vote
7
down vote
favorite
Can anyone see why this isn't working?
Its trying to do; if Column Name Contains the text 'Andy', then make a column called Andy and set that row = to 1
df.loc[df['Name'].str.contains(['Andy']),'Andy']=1
python string pandas series
edited 50 mins ago
jpp
88.1k195099
asked 1 hour ago
fred.schwartz
2597
2
I think you needdf.loc[df['Name'].str.contains('Andy'),'Andy']=1- remove
– jezrael
1 hour ago
Thanks thats great. Out of curiosity, can we ammend this to say if contains Andy and George?( ... make a column called Andy and = 1)
– fred.schwartz
1 hour ago
df.loc[df['Name'].str.contains('Andy'|'George'),'Andy']=1
– fred.schwartz
1 hour ago
I was thinking the above but its not working
– fred.schwartz
1 hour ago
df.loc[df['Name'].str.contains('Andy|George'),'Andy']=1
– jezrael
1 hour ago
add a comment |
up vote
7
down vote
favorite
up vote
7
down vote
favorite
Can anyone see why this isn't working?
Its trying to do; if Column Name Contains the text 'Andy', then make a column called Andy and set that row = to 1
df.loc[df['Name'].str.contains(['Andy']),'Andy']=1
python string pandas series
edited 50 mins ago
jpp
88.1k195099
asked 1 hour ago
fred.schwartz
2597
Can anyone see why this isn't working?
Its trying to do; if Column Name Contains the text 'Andy', then make a column called Andy and set that row = to 1
df.loc[df['Name'].str.contains(['Andy']),'Andy']=1
python string pandas series
python string pandas series
edited 50 mins ago
jpp
88.1k195099
asked 1 hour ago
fred.schwartz
2597
edited 50 mins ago
jpp
88.1k195099
asked 1 hour ago
fred.schwartz
2597
edited 50 mins ago
jpp
88.1k195099
edited 50 mins ago
jpp
88.1k195099
edited 50 mins ago
jpp
88.1k195099
88.1k195099
asked 1 hour ago
fred.schwartz
2597
asked 1 hour ago
fred.schwartz
2597
asked 1 hour ago
fred.schwartz
2597
2597
2
I think you needdf.loc[df['Name'].str.contains('Andy'),'Andy']=1- remove
– jezrael
1 hour ago
Thanks thats great. Out of curiosity, can we ammend this to say if contains Andy and George?( ... make a column called Andy and = 1)
– fred.schwartz
1 hour ago
df.loc[df['Name'].str.contains('Andy'|'George'),'Andy']=1
– fred.schwartz
1 hour ago
I was thinking the above but its not working
– fred.schwartz
1 hour ago
df.loc[df['Name'].str.contains('Andy|George'),'Andy']=1
– jezrael
1 hour ago
add a comment |
2
I think you needdf.loc[df['Name'].str.contains('Andy'),'Andy']=1- remove
– jezrael
1 hour ago
Thanks thats great. Out of curiosity, can we ammend this to say if contains Andy and George?( ... make a column called Andy and = 1)
– fred.schwartz
1 hour ago
df.loc[df['Name'].str.contains('Andy'|'George'),'Andy']=1
– fred.schwartz
1 hour ago
I was thinking the above but its not working
– fred.schwartz
1 hour ago
df.loc[df['Name'].str.contains('Andy|George'),'Andy']=1
– jezrael
1 hour ago
2
2
I think you need
df.loc[df['Name'].str.contains('Andy'),'Andy']=1 - remove – jezrael
1 hour ago
I think you need
df.loc[df['Name'].str.contains('Andy'),'Andy']=1 - remove – jezrael
1 hour ago
Thanks thats great. Out of curiosity, can we ammend this to say if contains Andy and George?( ... make a column called Andy and = 1)
– fred.schwartz
1 hour ago
Thanks thats great. Out of curiosity, can we ammend this to say if contains Andy and George?( ... make a column called Andy and = 1)
– fred.schwartz
1 hour ago
df.loc[df['Name'].str.contains('Andy'|'George'),'Andy']=1
– fred.schwartz
1 hour ago
df.loc[df['Name'].str.contains('Andy'|'George'),'Andy']=1
– fred.schwartz
1 hour ago
I was thinking the above but its not working
– fred.schwartz
1 hour ago
I was thinking the above but its not working
– fred.schwartz
1 hour ago
df.loc[df['Name'].str.contains('Andy|George'),'Andy']=1 – jezrael
1 hour ago
df.loc[df['Name'].str.contains('Andy|George'),'Andy']=1 – jezrael
1 hour ago
add a comment |
2 Answers
2
active
oldest
votes
up vote
5
down vote
accepted
You have to remove list, need only string:
df.loc[df['Name'].str.contains('Andy'),'Andy'] = 1
For multiple values chain by |:
df.loc[df['Name'].str.contains('Andy|George'),'Andy'] = 1
answered 1 hour ago
jezrael
315k22256333
add a comment |
up vote
3
down vote
pd.Series.str.contains requires for its pat argument a "Character sequence or regular expression", not a list.
Just use Boolean assignment and convert to int. This will set unmatched rows to 0. For example:
# Name includes 'Andy'
df['Andy'] = df['Name'].str.contains('Andy').astype(int)
# Name includes 'Andy' or 'George'
df['Andy'] = df['Name'].str.contains('Andy|George').astype(int)
answered 58 mins ago
jpp
88.1k195099
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
5
down vote
accepted
You have to remove list, need only string:
df.loc[df['Name'].str.contains('Andy'),'Andy'] = 1
For multiple values chain by |:
df.loc[df['Name'].str.contains('Andy|George'),'Andy'] = 1
answered 1 hour ago
jezrael
315k22256333
add a comment |
up vote
5
down vote
accepted
You have to remove list, need only string:
df.loc[df['Name'].str.contains('Andy'),'Andy'] = 1
For multiple values chain by |:
df.loc[df['Name'].str.contains('Andy|George'),'Andy'] = 1
answered 1 hour ago
jezrael
315k22256333
add a comment |
up vote
5
down vote
accepted
up vote
5
down vote
accepted
You have to remove list, need only string:
df.loc[df['Name'].str.contains('Andy'),'Andy'] = 1
For multiple values chain by |:
df.loc[df['Name'].str.contains('Andy|George'),'Andy'] = 1
answered 1 hour ago
jezrael
315k22256333
You have to remove list, need only string:
df.loc[df['Name'].str.contains('Andy'),'Andy'] = 1
For multiple values chain by |:
df.loc[df['Name'].str.contains('Andy|George'),'Andy'] = 1
answered 1 hour ago
jezrael
315k22256333
answered 1 hour ago
jezrael
315k22256333
answered 1 hour ago
jezrael
315k22256333
answered 1 hour ago
jezrael
315k22256333
315k22256333
add a comment |
add a comment |
up vote
3
down vote
pd.Series.str.contains requires for its pat argument a "Character sequence or regular expression", not a list.
Just use Boolean assignment and convert to int. This will set unmatched rows to 0. For example:
# Name includes 'Andy'
df['Andy'] = df['Name'].str.contains('Andy').astype(int)
# Name includes 'Andy' or 'George'
df['Andy'] = df['Name'].str.contains('Andy|George').astype(int)
answered 58 mins ago
jpp
88.1k195099
add a comment |
up vote
3
down vote
pd.Series.str.contains requires for its pat argument a "Character sequence or regular expression", not a list.
Just use Boolean assignment and convert to int. This will set unmatched rows to 0. For example:
# Name includes 'Andy'
df['Andy'] = df['Name'].str.contains('Andy').astype(int)
# Name includes 'Andy' or 'George'
df['Andy'] = df['Name'].str.contains('Andy|George').astype(int)
answered 58 mins ago
jpp
88.1k195099
add a comment |
up vote
3
down vote
up vote
3
down vote
pd.Series.str.contains requires for its pat argument a "Character sequence or regular expression", not a list.
Just use Boolean assignment and convert to int. This will set unmatched rows to 0. For example:
# Name includes 'Andy'
df['Andy'] = df['Name'].str.contains('Andy').astype(int)
# Name includes 'Andy' or 'George'
df['Andy'] = df['Name'].str.contains('Andy|George').astype(int)
answered 58 mins ago
jpp
88.1k195099
pd.Series.str.contains requires for its pat argument a "Character sequence or regular expression", not a list.
Just use Boolean assignment and convert to int. This will set unmatched rows to 0. For example:
# Name includes 'Andy'
df['Andy'] = df['Name'].str.contains('Andy').astype(int)
# Name includes 'Andy' or 'George'
df['Andy'] = df['Name'].str.contains('Andy|George').astype(int)
answered 58 mins ago
jpp
88.1k195099
answered 58 mins ago
jpp
88.1k195099
answered 58 mins ago
jpp
88.1k195099
answered 58 mins ago
jpp
88.1k195099
88.1k195099
add a comment |
add a comment |
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2
I think you need
df.loc[df['Name'].str.contains('Andy'),'Andy']=1- remove– jezrael
1 hour ago
Thanks thats great. Out of curiosity, can we ammend this to say if contains Andy and George?( ... make a column called Andy and = 1)
– fred.schwartz
1 hour ago
df.loc[df['Name'].str.contains('Andy'|'George'),'Andy']=1
– fred.schwartz
1 hour ago
I was thinking the above but its not working
– fred.schwartz
1 hour ago
df.loc[df['Name'].str.contains('Andy|George'),'Andy']=1– jezrael
1 hour ago