KDB: why am I getting a type error when upserting?











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1
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I specified the columns to be of type String. Why am I getting the following error:



q)test: ([key1:"s"$()] col1:"s"$();col2:"s"$();col3:"s"$())
q)`test upsert(`key1`col1`col2`col3)!(string "999"; string "693"; string "943";
string "249")

'type
[0] `test upsert(`key1`col1`col2`col3)!(string "999"; string "693"; string "9
43"; string "249")









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    up vote
    1
    down vote

    favorite












    I specified the columns to be of type String. Why am I getting the following error:



    q)test: ([key1:"s"$()] col1:"s"$();col2:"s"$();col3:"s"$())
    q)`test upsert(`key1`col1`col2`col3)!(string "999"; string "693"; string "943";
    string "249")

    'type
    [0] `test upsert(`key1`col1`col2`col3)!(string "999"; string "693"; string "9
    43"; string "249")









    share|improve this question
























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      I specified the columns to be of type String. Why am I getting the following error:



      q)test: ([key1:"s"$()] col1:"s"$();col2:"s"$();col3:"s"$())
      q)`test upsert(`key1`col1`col2`col3)!(string "999"; string "693"; string "943";
      string "249")

      'type
      [0] `test upsert(`key1`col1`col2`col3)!(string "999"; string "693"; string "9
      43"; string "249")









      share|improve this question













      I specified the columns to be of type String. Why am I getting the following error:



      q)test: ([key1:"s"$()] col1:"s"$();col2:"s"$();col3:"s"$())
      q)`test upsert(`key1`col1`col2`col3)!(string "999"; string "693"; string "943";
      string "249")

      'type
      [0] `test upsert(`key1`col1`col2`col3)!(string "999"; string "693"; string "9
      43"; string "249")






      kdb






      share|improve this question













      share|improve this question











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      share|improve this question










      asked Nov 22 at 16:25









      user3682563

      595




      595
























          2 Answers
          2






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          oldest

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          up vote
          2
          down vote



          accepted










          To do exactly this, you can remove the types of the list you defined in test:



          q)test: ([key1:()] col1:();col2:();col3:())
          q)test upsert (`key1`col1`col2`col3)!("999";"693";"943";"249")
          key1 | col1 col2 col3
          -----| -----------------
          "999"| "693" "943" "249"


          The reason you are getting a type error is because "s" corresponds to a list of symbols, not a list of characters. you can check this by using .Q.ty:



          q).Q.ty `symbol$()
          "s"
          q).Q.ty `char$()
          "c"


          It is (generally) not a great idea to set the keys as nested list of chars, you might find it better to set them as integers ("i") or longs ("j") as in:



          test: ([key1:"j"$()] col1:"j"$();col2:"j"$();col3:"j"$())


          Having the keys as integers/longs will make the upsert function behave nicely. Also note that a table is a list of dictionaries, so each dictionary can be upserted inidividually as well as a table being upserted:



          q)`test upsert (`key1`col1`col2`col3)!(9;4;6;2)
          `test
          q)test
          key1| col1 col2 col3
          ----| --------------
          9 | 4 6 2
          q)`test upsert (`key1`col1`col2`col3)!(8;6;2;3)
          `test
          q)test
          key1| col1 col2 col3
          ----| --------------
          9 | 4 6 2
          8 | 6 2 3
          q)`test upsert (`key1`col1`col2`col3)!(9;1;7;4)
          `test
          q)test
          key1| col1 col2 col3
          ----| --------------
          9 | 1 7 4
          8 | 6 2 3
          q)`test upsert ([key1: 8 7] col1:2 4; col2:9 3; col3:1 9)
          `test
          q)test
          key1| col1 col2 col3
          ----| --------------
          9 | 1 7 4
          8 | 2 9 1
          7 | 4 3 9





          share|improve this answer




























            up vote
            1
            down vote













            You have a few issues:




            • an array of chars in quotes is a string so no need to write string "abc"

            • string "aaa" will split the string out in strings of strings

            • your initial defined types are symbols "s" and not strings


            This will allow you to insert as symbols:



            q)test: ([key1:"s"$()] col1:"s"$();col2:"s"$();col3:"s"$())
            q)`test upsert(`key1`col1`col2`col3)!`$("999"; "693"; "943"; "249")
            `test


            This will keep them as strings:



            q)test: ([key1:()] col1:();col2:();col3:())
            q)`test upsert(`key1`col1`col2`col3)!("999"; "693"; "943"; "249")
            `test


            Have a look at the diffs in metas of the two



            HTH,
            Sean






            share|improve this answer





















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              2 Answers
              2






              active

              oldest

              votes








              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes








              up vote
              2
              down vote



              accepted










              To do exactly this, you can remove the types of the list you defined in test:



              q)test: ([key1:()] col1:();col2:();col3:())
              q)test upsert (`key1`col1`col2`col3)!("999";"693";"943";"249")
              key1 | col1 col2 col3
              -----| -----------------
              "999"| "693" "943" "249"


              The reason you are getting a type error is because "s" corresponds to a list of symbols, not a list of characters. you can check this by using .Q.ty:



              q).Q.ty `symbol$()
              "s"
              q).Q.ty `char$()
              "c"


              It is (generally) not a great idea to set the keys as nested list of chars, you might find it better to set them as integers ("i") or longs ("j") as in:



              test: ([key1:"j"$()] col1:"j"$();col2:"j"$();col3:"j"$())


              Having the keys as integers/longs will make the upsert function behave nicely. Also note that a table is a list of dictionaries, so each dictionary can be upserted inidividually as well as a table being upserted:



              q)`test upsert (`key1`col1`col2`col3)!(9;4;6;2)
              `test
              q)test
              key1| col1 col2 col3
              ----| --------------
              9 | 4 6 2
              q)`test upsert (`key1`col1`col2`col3)!(8;6;2;3)
              `test
              q)test
              key1| col1 col2 col3
              ----| --------------
              9 | 4 6 2
              8 | 6 2 3
              q)`test upsert (`key1`col1`col2`col3)!(9;1;7;4)
              `test
              q)test
              key1| col1 col2 col3
              ----| --------------
              9 | 1 7 4
              8 | 6 2 3
              q)`test upsert ([key1: 8 7] col1:2 4; col2:9 3; col3:1 9)
              `test
              q)test
              key1| col1 col2 col3
              ----| --------------
              9 | 1 7 4
              8 | 2 9 1
              7 | 4 3 9





              share|improve this answer

























                up vote
                2
                down vote



                accepted










                To do exactly this, you can remove the types of the list you defined in test:



                q)test: ([key1:()] col1:();col2:();col3:())
                q)test upsert (`key1`col1`col2`col3)!("999";"693";"943";"249")
                key1 | col1 col2 col3
                -----| -----------------
                "999"| "693" "943" "249"


                The reason you are getting a type error is because "s" corresponds to a list of symbols, not a list of characters. you can check this by using .Q.ty:



                q).Q.ty `symbol$()
                "s"
                q).Q.ty `char$()
                "c"


                It is (generally) not a great idea to set the keys as nested list of chars, you might find it better to set them as integers ("i") or longs ("j") as in:



                test: ([key1:"j"$()] col1:"j"$();col2:"j"$();col3:"j"$())


                Having the keys as integers/longs will make the upsert function behave nicely. Also note that a table is a list of dictionaries, so each dictionary can be upserted inidividually as well as a table being upserted:



                q)`test upsert (`key1`col1`col2`col3)!(9;4;6;2)
                `test
                q)test
                key1| col1 col2 col3
                ----| --------------
                9 | 4 6 2
                q)`test upsert (`key1`col1`col2`col3)!(8;6;2;3)
                `test
                q)test
                key1| col1 col2 col3
                ----| --------------
                9 | 4 6 2
                8 | 6 2 3
                q)`test upsert (`key1`col1`col2`col3)!(9;1;7;4)
                `test
                q)test
                key1| col1 col2 col3
                ----| --------------
                9 | 1 7 4
                8 | 6 2 3
                q)`test upsert ([key1: 8 7] col1:2 4; col2:9 3; col3:1 9)
                `test
                q)test
                key1| col1 col2 col3
                ----| --------------
                9 | 1 7 4
                8 | 2 9 1
                7 | 4 3 9





                share|improve this answer























                  up vote
                  2
                  down vote



                  accepted







                  up vote
                  2
                  down vote



                  accepted






                  To do exactly this, you can remove the types of the list you defined in test:



                  q)test: ([key1:()] col1:();col2:();col3:())
                  q)test upsert (`key1`col1`col2`col3)!("999";"693";"943";"249")
                  key1 | col1 col2 col3
                  -----| -----------------
                  "999"| "693" "943" "249"


                  The reason you are getting a type error is because "s" corresponds to a list of symbols, not a list of characters. you can check this by using .Q.ty:



                  q).Q.ty `symbol$()
                  "s"
                  q).Q.ty `char$()
                  "c"


                  It is (generally) not a great idea to set the keys as nested list of chars, you might find it better to set them as integers ("i") or longs ("j") as in:



                  test: ([key1:"j"$()] col1:"j"$();col2:"j"$();col3:"j"$())


                  Having the keys as integers/longs will make the upsert function behave nicely. Also note that a table is a list of dictionaries, so each dictionary can be upserted inidividually as well as a table being upserted:



                  q)`test upsert (`key1`col1`col2`col3)!(9;4;6;2)
                  `test
                  q)test
                  key1| col1 col2 col3
                  ----| --------------
                  9 | 4 6 2
                  q)`test upsert (`key1`col1`col2`col3)!(8;6;2;3)
                  `test
                  q)test
                  key1| col1 col2 col3
                  ----| --------------
                  9 | 4 6 2
                  8 | 6 2 3
                  q)`test upsert (`key1`col1`col2`col3)!(9;1;7;4)
                  `test
                  q)test
                  key1| col1 col2 col3
                  ----| --------------
                  9 | 1 7 4
                  8 | 6 2 3
                  q)`test upsert ([key1: 8 7] col1:2 4; col2:9 3; col3:1 9)
                  `test
                  q)test
                  key1| col1 col2 col3
                  ----| --------------
                  9 | 1 7 4
                  8 | 2 9 1
                  7 | 4 3 9





                  share|improve this answer












                  To do exactly this, you can remove the types of the list you defined in test:



                  q)test: ([key1:()] col1:();col2:();col3:())
                  q)test upsert (`key1`col1`col2`col3)!("999";"693";"943";"249")
                  key1 | col1 col2 col3
                  -----| -----------------
                  "999"| "693" "943" "249"


                  The reason you are getting a type error is because "s" corresponds to a list of symbols, not a list of characters. you can check this by using .Q.ty:



                  q).Q.ty `symbol$()
                  "s"
                  q).Q.ty `char$()
                  "c"


                  It is (generally) not a great idea to set the keys as nested list of chars, you might find it better to set them as integers ("i") or longs ("j") as in:



                  test: ([key1:"j"$()] col1:"j"$();col2:"j"$();col3:"j"$())


                  Having the keys as integers/longs will make the upsert function behave nicely. Also note that a table is a list of dictionaries, so each dictionary can be upserted inidividually as well as a table being upserted:



                  q)`test upsert (`key1`col1`col2`col3)!(9;4;6;2)
                  `test
                  q)test
                  key1| col1 col2 col3
                  ----| --------------
                  9 | 4 6 2
                  q)`test upsert (`key1`col1`col2`col3)!(8;6;2;3)
                  `test
                  q)test
                  key1| col1 col2 col3
                  ----| --------------
                  9 | 4 6 2
                  8 | 6 2 3
                  q)`test upsert (`key1`col1`col2`col3)!(9;1;7;4)
                  `test
                  q)test
                  key1| col1 col2 col3
                  ----| --------------
                  9 | 1 7 4
                  8 | 6 2 3
                  q)`test upsert ([key1: 8 7] col1:2 4; col2:9 3; col3:1 9)
                  `test
                  q)test
                  key1| col1 col2 col3
                  ----| --------------
                  9 | 1 7 4
                  8 | 2 9 1
                  7 | 4 3 9






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 22 at 16:57









                  Eliot Robinson

                  361




                  361
























                      up vote
                      1
                      down vote













                      You have a few issues:




                      • an array of chars in quotes is a string so no need to write string "abc"

                      • string "aaa" will split the string out in strings of strings

                      • your initial defined types are symbols "s" and not strings


                      This will allow you to insert as symbols:



                      q)test: ([key1:"s"$()] col1:"s"$();col2:"s"$();col3:"s"$())
                      q)`test upsert(`key1`col1`col2`col3)!`$("999"; "693"; "943"; "249")
                      `test


                      This will keep them as strings:



                      q)test: ([key1:()] col1:();col2:();col3:())
                      q)`test upsert(`key1`col1`col2`col3)!("999"; "693"; "943"; "249")
                      `test


                      Have a look at the diffs in metas of the two



                      HTH,
                      Sean






                      share|improve this answer

























                        up vote
                        1
                        down vote













                        You have a few issues:




                        • an array of chars in quotes is a string so no need to write string "abc"

                        • string "aaa" will split the string out in strings of strings

                        • your initial defined types are symbols "s" and not strings


                        This will allow you to insert as symbols:



                        q)test: ([key1:"s"$()] col1:"s"$();col2:"s"$();col3:"s"$())
                        q)`test upsert(`key1`col1`col2`col3)!`$("999"; "693"; "943"; "249")
                        `test


                        This will keep them as strings:



                        q)test: ([key1:()] col1:();col2:();col3:())
                        q)`test upsert(`key1`col1`col2`col3)!("999"; "693"; "943"; "249")
                        `test


                        Have a look at the diffs in metas of the two



                        HTH,
                        Sean






                        share|improve this answer























                          up vote
                          1
                          down vote










                          up vote
                          1
                          down vote









                          You have a few issues:




                          • an array of chars in quotes is a string so no need to write string "abc"

                          • string "aaa" will split the string out in strings of strings

                          • your initial defined types are symbols "s" and not strings


                          This will allow you to insert as symbols:



                          q)test: ([key1:"s"$()] col1:"s"$();col2:"s"$();col3:"s"$())
                          q)`test upsert(`key1`col1`col2`col3)!`$("999"; "693"; "943"; "249")
                          `test


                          This will keep them as strings:



                          q)test: ([key1:()] col1:();col2:();col3:())
                          q)`test upsert(`key1`col1`col2`col3)!("999"; "693"; "943"; "249")
                          `test


                          Have a look at the diffs in metas of the two



                          HTH,
                          Sean






                          share|improve this answer












                          You have a few issues:




                          • an array of chars in quotes is a string so no need to write string "abc"

                          • string "aaa" will split the string out in strings of strings

                          • your initial defined types are symbols "s" and not strings


                          This will allow you to insert as symbols:



                          q)test: ([key1:"s"$()] col1:"s"$();col2:"s"$();col3:"s"$())
                          q)`test upsert(`key1`col1`col2`col3)!`$("999"; "693"; "943"; "249")
                          `test


                          This will keep them as strings:



                          q)test: ([key1:()] col1:();col2:();col3:())
                          q)`test upsert(`key1`col1`col2`col3)!("999"; "693"; "943"; "249")
                          `test


                          Have a look at the diffs in metas of the two



                          HTH,
                          Sean







                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Nov 22 at 16:50









                          Sean O'Hagan

                          1,544311




                          1,544311






























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