Calculate Ratios in columns, based on other columns
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0
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I am facing an thinking & programming problem. See below my question, I have no clue what a proper approach is (played with DPLYR's group_by, but without results). Many thanks in advance for trying helping me out here!
I have a data set like this:
Numbers Area Cluster
1 A 1
0.8 A 1
0.78 A 1
0.7 B 1
0.4 A 2
0 C 1
I want to calculate two new columns:
- Show the % of Area's occurring in a specific cluster (Column_Example_1)
- Per Cluster, a new index of the column numbers (in a range from 1 - 0) (Column_example_2). The new ratio should be based on the column Numbers #note: in the example it is just an example, it could also done differently, but we I want to make sure that the column Numbers is leading)
The result should be like this:
Numbers Area Cluster Example_1 Example_2
1 A 1 60% #5x cluster 1, and 3x Area A) 1
0.8 A 1 60% 0.8
0.78 A 1 60% 0.78
0.7 B 1 20% 0.7
0.4 A 2 100% 1
0 C 1 20% 0
r
add a comment |
up vote
0
down vote
favorite
I am facing an thinking & programming problem. See below my question, I have no clue what a proper approach is (played with DPLYR's group_by, but without results). Many thanks in advance for trying helping me out here!
I have a data set like this:
Numbers Area Cluster
1 A 1
0.8 A 1
0.78 A 1
0.7 B 1
0.4 A 2
0 C 1
I want to calculate two new columns:
- Show the % of Area's occurring in a specific cluster (Column_Example_1)
- Per Cluster, a new index of the column numbers (in a range from 1 - 0) (Column_example_2). The new ratio should be based on the column Numbers #note: in the example it is just an example, it could also done differently, but we I want to make sure that the column Numbers is leading)
The result should be like this:
Numbers Area Cluster Example_1 Example_2
1 A 1 60% #5x cluster 1, and 3x Area A) 1
0.8 A 1 60% 0.8
0.78 A 1 60% 0.78
0.7 B 1 20% 0.7
0.4 A 2 100% 1
0 C 1 20% 0
r
Can you explain how you arrive at Example_2?
– erocoar
Nov 22 at 15:32
df %>% group_by(Cluster) %>% mutate(Example_2 = ifelse(row_number()==1, 1, Numbers))
?
– CER
Nov 22 at 15:43
Hi @erocoar; yes, in this example it was to show the sequence of a specific cluster, based on the column numbers. (So if numbers is between 1 - 0, I want to have something similar for each cluster (so the highest value of a specific cluster should have a 1, the lowest should have a 0, and the rest between those two numbers, based on their number score of course). Sorry, hope that this explanation make sense for you.
– R overflow
Nov 23 at 7:29
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I am facing an thinking & programming problem. See below my question, I have no clue what a proper approach is (played with DPLYR's group_by, but without results). Many thanks in advance for trying helping me out here!
I have a data set like this:
Numbers Area Cluster
1 A 1
0.8 A 1
0.78 A 1
0.7 B 1
0.4 A 2
0 C 1
I want to calculate two new columns:
- Show the % of Area's occurring in a specific cluster (Column_Example_1)
- Per Cluster, a new index of the column numbers (in a range from 1 - 0) (Column_example_2). The new ratio should be based on the column Numbers #note: in the example it is just an example, it could also done differently, but we I want to make sure that the column Numbers is leading)
The result should be like this:
Numbers Area Cluster Example_1 Example_2
1 A 1 60% #5x cluster 1, and 3x Area A) 1
0.8 A 1 60% 0.8
0.78 A 1 60% 0.78
0.7 B 1 20% 0.7
0.4 A 2 100% 1
0 C 1 20% 0
r
I am facing an thinking & programming problem. See below my question, I have no clue what a proper approach is (played with DPLYR's group_by, but without results). Many thanks in advance for trying helping me out here!
I have a data set like this:
Numbers Area Cluster
1 A 1
0.8 A 1
0.78 A 1
0.7 B 1
0.4 A 2
0 C 1
I want to calculate two new columns:
- Show the % of Area's occurring in a specific cluster (Column_Example_1)
- Per Cluster, a new index of the column numbers (in a range from 1 - 0) (Column_example_2). The new ratio should be based on the column Numbers #note: in the example it is just an example, it could also done differently, but we I want to make sure that the column Numbers is leading)
The result should be like this:
Numbers Area Cluster Example_1 Example_2
1 A 1 60% #5x cluster 1, and 3x Area A) 1
0.8 A 1 60% 0.8
0.78 A 1 60% 0.78
0.7 B 1 20% 0.7
0.4 A 2 100% 1
0 C 1 20% 0
r
r
asked Nov 22 at 15:18
R overflow
652211
652211
Can you explain how you arrive at Example_2?
– erocoar
Nov 22 at 15:32
df %>% group_by(Cluster) %>% mutate(Example_2 = ifelse(row_number()==1, 1, Numbers))
?
– CER
Nov 22 at 15:43
Hi @erocoar; yes, in this example it was to show the sequence of a specific cluster, based on the column numbers. (So if numbers is between 1 - 0, I want to have something similar for each cluster (so the highest value of a specific cluster should have a 1, the lowest should have a 0, and the rest between those two numbers, based on their number score of course). Sorry, hope that this explanation make sense for you.
– R overflow
Nov 23 at 7:29
add a comment |
Can you explain how you arrive at Example_2?
– erocoar
Nov 22 at 15:32
df %>% group_by(Cluster) %>% mutate(Example_2 = ifelse(row_number()==1, 1, Numbers))
?
– CER
Nov 22 at 15:43
Hi @erocoar; yes, in this example it was to show the sequence of a specific cluster, based on the column numbers. (So if numbers is between 1 - 0, I want to have something similar for each cluster (so the highest value of a specific cluster should have a 1, the lowest should have a 0, and the rest between those two numbers, based on their number score of course). Sorry, hope that this explanation make sense for you.
– R overflow
Nov 23 at 7:29
Can you explain how you arrive at Example_2?
– erocoar
Nov 22 at 15:32
Can you explain how you arrive at Example_2?
– erocoar
Nov 22 at 15:32
df %>% group_by(Cluster) %>% mutate(Example_2 = ifelse(row_number()==1, 1, Numbers))
?– CER
Nov 22 at 15:43
df %>% group_by(Cluster) %>% mutate(Example_2 = ifelse(row_number()==1, 1, Numbers))
?– CER
Nov 22 at 15:43
Hi @erocoar; yes, in this example it was to show the sequence of a specific cluster, based on the column numbers. (So if numbers is between 1 - 0, I want to have something similar for each cluster (so the highest value of a specific cluster should have a 1, the lowest should have a 0, and the rest between those two numbers, based on their number score of course). Sorry, hope that this explanation make sense for you.
– R overflow
Nov 23 at 7:29
Hi @erocoar; yes, in this example it was to show the sequence of a specific cluster, based on the column numbers. (So if numbers is between 1 - 0, I want to have something similar for each cluster (so the highest value of a specific cluster should have a 1, the lowest should have a 0, and the rest between those two numbers, based on their number score of course). Sorry, hope that this explanation make sense for you.
– R overflow
Nov 23 at 7:29
add a comment |
2 Answers
2
active
oldest
votes
up vote
2
down vote
accepted
Since you want to keep all rows, you can calculate the relative frequencies as follows:
library(tidyverse)
df <- data.frame(numbers = c(1, .8, .78, .7, .4, 0),
area = c("A", "A", "A", "B", "A", "C"),
cluster = c(1, 1, 1, 1, 2, 1))
df %>%
group_by(cluster) %>%
mutate(example_1 = n()) %>%
group_by(area, cluster) %>%
mutate(example_1 = n() / example_1)
# A tibble: 6 x 4
# Groups: area, cluster [4]
numbers area cluster example_1
<dbl> <fct> <dbl> <dbl>
1 1 A 1 0.6
2 0.8 A 1 0.6
3 0.78 A 1 0.6
4 0.7 B 1 0.2
5 0.4 A 2 1
6 0 C 1 0.2
Thanks! The column Example_1 totally works! Do you also know how I can make the example_2 column with your dplyr approach? Really appreciated!!
– R overflow
Nov 23 at 7:26
This will do the trick. Thanks! library(scales) test <- test %>% group_by(cluster) %>% mutate(example_2 = rescale(numbers ))
– R overflow
Nov 23 at 9:03
add a comment |
up vote
1
down vote
You can also do with data.table
:
library(magrittr)
library(data.table)
df <- data.table(Numbers = c(1, .8, .78, .7, .4, 0),
Area = c(rep("A", 3), "B", "A", "C"),
Cluster = c(rep(1, 4), 2, 1))
df[, N := .N, by = c("Cluster")] %>%
.[, Example_1 := .N/N, by = c("Cluster", "Area")] %>%
.[, `:=`(N = NULL, Example_2 = Numbers)]
Output:
> df
Numbers Area Cluster Example_1 Example_2
1: 1.00 A 1 0.6 1.00
2: 0.80 A 1 0.6 0.80
3: 0.78 A 1 0.6 0.78
4: 0.70 B 1 0.2 0.70
5: 0.40 A 2 1.0 0.40
6: 0.00 C 1 0.2 0.00
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
accepted
Since you want to keep all rows, you can calculate the relative frequencies as follows:
library(tidyverse)
df <- data.frame(numbers = c(1, .8, .78, .7, .4, 0),
area = c("A", "A", "A", "B", "A", "C"),
cluster = c(1, 1, 1, 1, 2, 1))
df %>%
group_by(cluster) %>%
mutate(example_1 = n()) %>%
group_by(area, cluster) %>%
mutate(example_1 = n() / example_1)
# A tibble: 6 x 4
# Groups: area, cluster [4]
numbers area cluster example_1
<dbl> <fct> <dbl> <dbl>
1 1 A 1 0.6
2 0.8 A 1 0.6
3 0.78 A 1 0.6
4 0.7 B 1 0.2
5 0.4 A 2 1
6 0 C 1 0.2
Thanks! The column Example_1 totally works! Do you also know how I can make the example_2 column with your dplyr approach? Really appreciated!!
– R overflow
Nov 23 at 7:26
This will do the trick. Thanks! library(scales) test <- test %>% group_by(cluster) %>% mutate(example_2 = rescale(numbers ))
– R overflow
Nov 23 at 9:03
add a comment |
up vote
2
down vote
accepted
Since you want to keep all rows, you can calculate the relative frequencies as follows:
library(tidyverse)
df <- data.frame(numbers = c(1, .8, .78, .7, .4, 0),
area = c("A", "A", "A", "B", "A", "C"),
cluster = c(1, 1, 1, 1, 2, 1))
df %>%
group_by(cluster) %>%
mutate(example_1 = n()) %>%
group_by(area, cluster) %>%
mutate(example_1 = n() / example_1)
# A tibble: 6 x 4
# Groups: area, cluster [4]
numbers area cluster example_1
<dbl> <fct> <dbl> <dbl>
1 1 A 1 0.6
2 0.8 A 1 0.6
3 0.78 A 1 0.6
4 0.7 B 1 0.2
5 0.4 A 2 1
6 0 C 1 0.2
Thanks! The column Example_1 totally works! Do you also know how I can make the example_2 column with your dplyr approach? Really appreciated!!
– R overflow
Nov 23 at 7:26
This will do the trick. Thanks! library(scales) test <- test %>% group_by(cluster) %>% mutate(example_2 = rescale(numbers ))
– R overflow
Nov 23 at 9:03
add a comment |
up vote
2
down vote
accepted
up vote
2
down vote
accepted
Since you want to keep all rows, you can calculate the relative frequencies as follows:
library(tidyverse)
df <- data.frame(numbers = c(1, .8, .78, .7, .4, 0),
area = c("A", "A", "A", "B", "A", "C"),
cluster = c(1, 1, 1, 1, 2, 1))
df %>%
group_by(cluster) %>%
mutate(example_1 = n()) %>%
group_by(area, cluster) %>%
mutate(example_1 = n() / example_1)
# A tibble: 6 x 4
# Groups: area, cluster [4]
numbers area cluster example_1
<dbl> <fct> <dbl> <dbl>
1 1 A 1 0.6
2 0.8 A 1 0.6
3 0.78 A 1 0.6
4 0.7 B 1 0.2
5 0.4 A 2 1
6 0 C 1 0.2
Since you want to keep all rows, you can calculate the relative frequencies as follows:
library(tidyverse)
df <- data.frame(numbers = c(1, .8, .78, .7, .4, 0),
area = c("A", "A", "A", "B", "A", "C"),
cluster = c(1, 1, 1, 1, 2, 1))
df %>%
group_by(cluster) %>%
mutate(example_1 = n()) %>%
group_by(area, cluster) %>%
mutate(example_1 = n() / example_1)
# A tibble: 6 x 4
# Groups: area, cluster [4]
numbers area cluster example_1
<dbl> <fct> <dbl> <dbl>
1 1 A 1 0.6
2 0.8 A 1 0.6
3 0.78 A 1 0.6
4 0.7 B 1 0.2
5 0.4 A 2 1
6 0 C 1 0.2
answered Nov 22 at 15:34
erocoar
3,67511233
3,67511233
Thanks! The column Example_1 totally works! Do you also know how I can make the example_2 column with your dplyr approach? Really appreciated!!
– R overflow
Nov 23 at 7:26
This will do the trick. Thanks! library(scales) test <- test %>% group_by(cluster) %>% mutate(example_2 = rescale(numbers ))
– R overflow
Nov 23 at 9:03
add a comment |
Thanks! The column Example_1 totally works! Do you also know how I can make the example_2 column with your dplyr approach? Really appreciated!!
– R overflow
Nov 23 at 7:26
This will do the trick. Thanks! library(scales) test <- test %>% group_by(cluster) %>% mutate(example_2 = rescale(numbers ))
– R overflow
Nov 23 at 9:03
Thanks! The column Example_1 totally works! Do you also know how I can make the example_2 column with your dplyr approach? Really appreciated!!
– R overflow
Nov 23 at 7:26
Thanks! The column Example_1 totally works! Do you also know how I can make the example_2 column with your dplyr approach? Really appreciated!!
– R overflow
Nov 23 at 7:26
This will do the trick. Thanks! library(scales) test <- test %>% group_by(cluster) %>% mutate(example_2 = rescale(numbers ))
– R overflow
Nov 23 at 9:03
This will do the trick. Thanks! library(scales) test <- test %>% group_by(cluster) %>% mutate(example_2 = rescale(numbers ))
– R overflow
Nov 23 at 9:03
add a comment |
up vote
1
down vote
You can also do with data.table
:
library(magrittr)
library(data.table)
df <- data.table(Numbers = c(1, .8, .78, .7, .4, 0),
Area = c(rep("A", 3), "B", "A", "C"),
Cluster = c(rep(1, 4), 2, 1))
df[, N := .N, by = c("Cluster")] %>%
.[, Example_1 := .N/N, by = c("Cluster", "Area")] %>%
.[, `:=`(N = NULL, Example_2 = Numbers)]
Output:
> df
Numbers Area Cluster Example_1 Example_2
1: 1.00 A 1 0.6 1.00
2: 0.80 A 1 0.6 0.80
3: 0.78 A 1 0.6 0.78
4: 0.70 B 1 0.2 0.70
5: 0.40 A 2 1.0 0.40
6: 0.00 C 1 0.2 0.00
add a comment |
up vote
1
down vote
You can also do with data.table
:
library(magrittr)
library(data.table)
df <- data.table(Numbers = c(1, .8, .78, .7, .4, 0),
Area = c(rep("A", 3), "B", "A", "C"),
Cluster = c(rep(1, 4), 2, 1))
df[, N := .N, by = c("Cluster")] %>%
.[, Example_1 := .N/N, by = c("Cluster", "Area")] %>%
.[, `:=`(N = NULL, Example_2 = Numbers)]
Output:
> df
Numbers Area Cluster Example_1 Example_2
1: 1.00 A 1 0.6 1.00
2: 0.80 A 1 0.6 0.80
3: 0.78 A 1 0.6 0.78
4: 0.70 B 1 0.2 0.70
5: 0.40 A 2 1.0 0.40
6: 0.00 C 1 0.2 0.00
add a comment |
up vote
1
down vote
up vote
1
down vote
You can also do with data.table
:
library(magrittr)
library(data.table)
df <- data.table(Numbers = c(1, .8, .78, .7, .4, 0),
Area = c(rep("A", 3), "B", "A", "C"),
Cluster = c(rep(1, 4), 2, 1))
df[, N := .N, by = c("Cluster")] %>%
.[, Example_1 := .N/N, by = c("Cluster", "Area")] %>%
.[, `:=`(N = NULL, Example_2 = Numbers)]
Output:
> df
Numbers Area Cluster Example_1 Example_2
1: 1.00 A 1 0.6 1.00
2: 0.80 A 1 0.6 0.80
3: 0.78 A 1 0.6 0.78
4: 0.70 B 1 0.2 0.70
5: 0.40 A 2 1.0 0.40
6: 0.00 C 1 0.2 0.00
You can also do with data.table
:
library(magrittr)
library(data.table)
df <- data.table(Numbers = c(1, .8, .78, .7, .4, 0),
Area = c(rep("A", 3), "B", "A", "C"),
Cluster = c(rep(1, 4), 2, 1))
df[, N := .N, by = c("Cluster")] %>%
.[, Example_1 := .N/N, by = c("Cluster", "Area")] %>%
.[, `:=`(N = NULL, Example_2 = Numbers)]
Output:
> df
Numbers Area Cluster Example_1 Example_2
1: 1.00 A 1 0.6 1.00
2: 0.80 A 1 0.6 0.80
3: 0.78 A 1 0.6 0.78
4: 0.70 B 1 0.2 0.70
5: 0.40 A 2 1.0 0.40
6: 0.00 C 1 0.2 0.00
answered Nov 22 at 15:46
JdeMello
331111
331111
add a comment |
add a comment |
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Can you explain how you arrive at Example_2?
– erocoar
Nov 22 at 15:32
df %>% group_by(Cluster) %>% mutate(Example_2 = ifelse(row_number()==1, 1, Numbers))
?– CER
Nov 22 at 15:43
Hi @erocoar; yes, in this example it was to show the sequence of a specific cluster, based on the column numbers. (So if numbers is between 1 - 0, I want to have something similar for each cluster (so the highest value of a specific cluster should have a 1, the lowest should have a 0, and the rest between those two numbers, based on their number score of course). Sorry, hope that this explanation make sense for you.
– R overflow
Nov 23 at 7:29