Square brackets getting changed to encoded character [WordPress]
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0
down vote
favorite
Here is the problem, I have a JS code block that I would very much like to keep inline for speed reasons. This has not presented a problem in the past but for this specific function this is happening. I am using the PHP Output Buffer to render this through a shortcode.
Code that is rendered:
function get_price(arr, val) {
var price = Object.keys(arr).reduce((a, c) => {
var s = c.trim();
if (/d+-d+/.test(s)) {
var range = s.split("-");
if (+val >= parseInt(range[0]) && +val <= parseInt(range[1])) {
a = arr[c];
}
} else {
s = s.replace(/D/g, "");
if (+val >= +s) {
a = arr[c];
}
}
return a;
}, 0);
return price;
}
Code that is sent:
function get_price(arr, val) {
var price = Object.keys(arr).reduce((a, c) => {
var s = c.trim();
if (/d+-d+/.test(s)) {
var range = s.split("-");
if (+val >= parseInt(range[0]) && +val <= parseInt(range[1])) {
a = arr[c];
}
} else {
s = s.replace(/D/g, "");
if (+val >= +s) {
a = arr[c];
}
}
return a;
}, 0);
return price;
}
I am at my wits end as too why this is happening so any help is appreciated!
I can also send more code if needed but don't want to overload my question with unnecessary code.
javascript wordpress shortcode
asked Nov 21 at 20:57
Top-Bot
160112
add a comment |
up vote
0
down vote
favorite
Here is the problem, I have a JS code block that I would very much like to keep inline for speed reasons. This has not presented a problem in the past but for this specific function this is happening. I am using the PHP Output Buffer to render this through a shortcode.
Code that is rendered:
function get_price(arr, val) {
var price = Object.keys(arr).reduce((a, c) => {
var s = c.trim();
if (/d+-d+/.test(s)) {
var range = s.split("-");
if (+val >= parseInt(range[0]) && +val <= parseInt(range[1])) {
a = arr[c];
}
} else {
s = s.replace(/D/g, "");
if (+val >= +s) {
a = arr[c];
}
}
return a;
}, 0);
return price;
}
Code that is sent:
function get_price(arr, val) {
var price = Object.keys(arr).reduce((a, c) => {
var s = c.trim();
if (/d+-d+/.test(s)) {
var range = s.split("-");
if (+val >= parseInt(range[0]) && +val <= parseInt(range[1])) {
a = arr[c];
}
} else {
s = s.replace(/D/g, "");
if (+val >= +s) {
a = arr[c];
}
}
return a;
}, 0);
return price;
}
I am at my wits end as too why this is happening so any help is appreciated!
I can also send more code if needed but don't want to overload my question with unnecessary code.
javascript wordpress shortcode
asked Nov 21 at 20:57
Top-Bot
160112
Can you try escaping the square brackets (with )?
– zipkundan
Nov 21 at 21:01
Why are only some of the brackets affected do you think?
– Top-Bot
Nov 21 at 21:05
I guess thats because you are trying render it through shortcode. Shortcode itself is rendered via square brackets. Though I am not very sure about the reason, its just the very first thought top of the mind.
– zipkundan
Nov 21 at 21:10
If that were the case then it should be changing all the square brackets but it is not
– Top-Bot
Nov 21 at 21:16
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Here is the problem, I have a JS code block that I would very much like to keep inline for speed reasons. This has not presented a problem in the past but for this specific function this is happening. I am using the PHP Output Buffer to render this through a shortcode.
Code that is rendered:
function get_price(arr, val) {
var price = Object.keys(arr).reduce((a, c) => {
var s = c.trim();
if (/d+-d+/.test(s)) {
var range = s.split("-");
if (+val >= parseInt(range[0]) && +val <= parseInt(range[1])) {
a = arr[c];
}
} else {
s = s.replace(/D/g, "");
if (+val >= +s) {
a = arr[c];
}
}
return a;
}, 0);
return price;
}
Code that is sent:
function get_price(arr, val) {
var price = Object.keys(arr).reduce((a, c) => {
var s = c.trim();
if (/d+-d+/.test(s)) {
var range = s.split("-");
if (+val >= parseInt(range[0]) && +val <= parseInt(range[1])) {
a = arr[c];
}
} else {
s = s.replace(/D/g, "");
if (+val >= +s) {
a = arr[c];
}
}
return a;
}, 0);
return price;
}
I am at my wits end as too why this is happening so any help is appreciated!
I can also send more code if needed but don't want to overload my question with unnecessary code.
javascript wordpress shortcode
asked Nov 21 at 20:57
Top-Bot
160112
Here is the problem, I have a JS code block that I would very much like to keep inline for speed reasons. This has not presented a problem in the past but for this specific function this is happening. I am using the PHP Output Buffer to render this through a shortcode.
Code that is rendered:
function get_price(arr, val) {
var price = Object.keys(arr).reduce((a, c) => {
var s = c.trim();
if (/d+-d+/.test(s)) {
var range = s.split("-");
if (+val >= parseInt(range[0]) && +val <= parseInt(range[1])) {
a = arr[c];
}
} else {
s = s.replace(/D/g, "");
if (+val >= +s) {
a = arr[c];
}
}
return a;
}, 0);
return price;
}
Code that is sent:
function get_price(arr, val) {
var price = Object.keys(arr).reduce((a, c) => {
var s = c.trim();
if (/d+-d+/.test(s)) {
var range = s.split("-");
if (+val >= parseInt(range[0]) && +val <= parseInt(range[1])) {
a = arr[c];
}
} else {
s = s.replace(/D/g, "");
if (+val >= +s) {
a = arr[c];
}
}
return a;
}, 0);
return price;
}
I am at my wits end as too why this is happening so any help is appreciated!
I can also send more code if needed but don't want to overload my question with unnecessary code.
javascript wordpress shortcode
javascript wordpress shortcode
asked Nov 21 at 20:57
Top-Bot
160112
asked Nov 21 at 20:57
Top-Bot
160112
asked Nov 21 at 20:57
Top-Bot
160112
asked Nov 21 at 20:57
Top-Bot
160112
asked Nov 21 at 20:57
Top-Bot
160112
160112
Can you try escaping the square brackets (with )?
– zipkundan
Nov 21 at 21:01
Why are only some of the brackets affected do you think?
– Top-Bot
Nov 21 at 21:05
I guess thats because you are trying render it through shortcode. Shortcode itself is rendered via square brackets. Though I am not very sure about the reason, its just the very first thought top of the mind.
– zipkundan
Nov 21 at 21:10
If that were the case then it should be changing all the square brackets but it is not
– Top-Bot
Nov 21 at 21:16
add a comment |
Can you try escaping the square brackets (with )?
– zipkundan
Nov 21 at 21:01
Why are only some of the brackets affected do you think?
– Top-Bot
Nov 21 at 21:05
I guess thats because you are trying render it through shortcode. Shortcode itself is rendered via square brackets. Though I am not very sure about the reason, its just the very first thought top of the mind.
– zipkundan
Nov 21 at 21:10
If that were the case then it should be changing all the square brackets but it is not
– Top-Bot
Nov 21 at 21:16
Can you try escaping the square brackets (with )?
– zipkundan
Nov 21 at 21:01
Can you try escaping the square brackets (with )?
– zipkundan
Nov 21 at 21:01
Why are only some of the brackets affected do you think?
– Top-Bot
Nov 21 at 21:05
Why are only some of the brackets affected do you think?
– Top-Bot
Nov 21 at 21:05
I guess thats because you are trying render it through shortcode. Shortcode itself is rendered via square brackets. Though I am not very sure about the reason, its just the very first thought top of the mind.
– zipkundan
Nov 21 at 21:10
I guess thats because you are trying render it through shortcode. Shortcode itself is rendered via square brackets. Though I am not very sure about the reason, its just the very first thought top of the mind.
– zipkundan
Nov 21 at 21:10
If that were the case then it should be changing all the square brackets but it is not
– Top-Bot
Nov 21 at 21:16
If that were the case then it should be changing all the square brackets but it is not
– Top-Bot
Nov 21 at 21:16
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
So... Not sure why this worked but I converted the 2 offending areas into JS vars and then the code was no longer getting encoded.
function get_price(arr, val) {
var price = Object.keys(arr).reduce((a, c) => {
var s = c.trim();
if (/d+-d+/.test(s)) {
var range = s.split("-");
var t1 = parseInt(range[1]); // new added var
var t2 = arr[c]; // new added var
if (+val >= parseInt(range[0]) && +val <= t1) { // replaced code with t1 here
a = t2; // replaced code with t2 here
}
} else {
s = s.replace(/D/g, "");
if (+val >= +s) {
a = arr[c];
}
}
return a;
}, 0);
return price;
}
If anyone know why and wants to help the universe by sharing their knowledge then go right ahead. If not then hopefully this helps someone!
answered Nov 21 at 21:27
Top-Bot
160112
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
So... Not sure why this worked but I converted the 2 offending areas into JS vars and then the code was no longer getting encoded.
function get_price(arr, val) {
var price = Object.keys(arr).reduce((a, c) => {
var s = c.trim();
if (/d+-d+/.test(s)) {
var range = s.split("-");
var t1 = parseInt(range[1]); // new added var
var t2 = arr[c]; // new added var
if (+val >= parseInt(range[0]) && +val <= t1) { // replaced code with t1 here
a = t2; // replaced code with t2 here
}
} else {
s = s.replace(/D/g, "");
if (+val >= +s) {
a = arr[c];
}
}
return a;
}, 0);
return price;
}
If anyone know why and wants to help the universe by sharing their knowledge then go right ahead. If not then hopefully this helps someone!
answered Nov 21 at 21:27
Top-Bot
160112
add a comment |
up vote
0
down vote
So... Not sure why this worked but I converted the 2 offending areas into JS vars and then the code was no longer getting encoded.
function get_price(arr, val) {
var price = Object.keys(arr).reduce((a, c) => {
var s = c.trim();
if (/d+-d+/.test(s)) {
var range = s.split("-");
var t1 = parseInt(range[1]); // new added var
var t2 = arr[c]; // new added var
if (+val >= parseInt(range[0]) && +val <= t1) { // replaced code with t1 here
a = t2; // replaced code with t2 here
}
} else {
s = s.replace(/D/g, "");
if (+val >= +s) {
a = arr[c];
}
}
return a;
}, 0);
return price;
}
If anyone know why and wants to help the universe by sharing their knowledge then go right ahead. If not then hopefully this helps someone!
answered Nov 21 at 21:27
Top-Bot
160112
add a comment |
up vote
0
down vote
up vote
0
down vote
So... Not sure why this worked but I converted the 2 offending areas into JS vars and then the code was no longer getting encoded.
function get_price(arr, val) {
var price = Object.keys(arr).reduce((a, c) => {
var s = c.trim();
if (/d+-d+/.test(s)) {
var range = s.split("-");
var t1 = parseInt(range[1]); // new added var
var t2 = arr[c]; // new added var
if (+val >= parseInt(range[0]) && +val <= t1) { // replaced code with t1 here
a = t2; // replaced code with t2 here
}
} else {
s = s.replace(/D/g, "");
if (+val >= +s) {
a = arr[c];
}
}
return a;
}, 0);
return price;
}
If anyone know why and wants to help the universe by sharing their knowledge then go right ahead. If not then hopefully this helps someone!
answered Nov 21 at 21:27
Top-Bot
160112
So... Not sure why this worked but I converted the 2 offending areas into JS vars and then the code was no longer getting encoded.
function get_price(arr, val) {
var price = Object.keys(arr).reduce((a, c) => {
var s = c.trim();
if (/d+-d+/.test(s)) {
var range = s.split("-");
var t1 = parseInt(range[1]); // new added var
var t2 = arr[c]; // new added var
if (+val >= parseInt(range[0]) && +val <= t1) { // replaced code with t1 here
a = t2; // replaced code with t2 here
}
} else {
s = s.replace(/D/g, "");
if (+val >= +s) {
a = arr[c];
}
}
return a;
}, 0);
return price;
}
If anyone know why and wants to help the universe by sharing their knowledge then go right ahead. If not then hopefully this helps someone!
answered Nov 21 at 21:27
Top-Bot
160112
edited Nov 21 at 21:34
answered Nov 21 at 21:27
Top-Bot
160112
answered Nov 21 at 21:27
Top-Bot
160112
answered Nov 21 at 21:27
Top-Bot
160112
160112
add a comment |
add a comment |
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Can you try escaping the square brackets (with )?
– zipkundan
Nov 21 at 21:01
Why are only some of the brackets affected do you think?
– Top-Bot
Nov 21 at 21:05
I guess thats because you are trying render it through shortcode. Shortcode itself is rendered via square brackets. Though I am not very sure about the reason, its just the very first thought top of the mind.
– zipkundan
Nov 21 at 21:10
If that were the case then it should be changing all the square brackets but it is not
– Top-Bot
Nov 21 at 21:16