Alternatives of lists vs Alternatives of strings











up vote
2
down vote

favorite












Obviously I am missing something obvious.



I have:



lis = {"a"}|{"b"}|{"c"}


but I want:



lis2 = "a"|"b"|"c"


Thanks as always for suggestions...






list-manipulation







share|improve this question


























    up vote
    2
    down vote

    favorite












    Obviously I am missing something obvious.



    I have:



    lis = {"a"}|{"b"}|{"c"}


    but I want:



    lis2 = "a"|"b"|"c"


    Thanks as always for suggestions...






    list-manipulation







    share|improve this question
























      up vote
      2
      down vote

      favorite









      up vote
      2
      down vote

      favorite











      Obviously I am missing something obvious.



      I have:



      lis = {"a"}|{"b"}|{"c"}


      but I want:



      lis2 = "a"|"b"|"c"


      Thanks as always for suggestions...






      list-manipulation







      share|improve this question













      Obviously I am missing something obvious.



      I have:



      lis = {"a"}|{"b"}|{"c"}


      but I want:



      lis2 = "a"|"b"|"c"


      Thanks as always for suggestions...






      list-manipulation




      list-manipulation






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 3 hours ago









      Suite401

      922312




      922312






















          2 Answers
          2






          active

          oldest

          votes

















          up vote
          3
          down vote



          accepted










          Use lis[[All, 1]] or First /@ list. See Part and First.






          share|improve this answer




























            up vote
            2
            down vote













            You can also Apply (@@@) Sequence at level 1:



            Sequence @@@ lis



            "a" | "b" | "c"




            or use ReplaceAll to replace List with Sequence: 



            lis /. List -> Sequence



            "a" | "b" | "c"







            share|improve this answer























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              2 Answers
              2






              active

              oldest

              votes








              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes








              up vote
              3
              down vote



              accepted










              Use lis[[All, 1]] or First /@ list. See Part and First.






              share|improve this answer

























                up vote
                3
                down vote



                accepted










                Use lis[[All, 1]] or First /@ list. See Part and First.






                share|improve this answer























                  up vote
                  3
                  down vote



                  accepted







                  up vote
                  3
                  down vote



                  accepted






                  Use lis[[All, 1]] or First /@ list. See Part and First.






                  share|improve this answer












                  Use lis[[All, 1]] or First /@ list. See Part and First.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 2 hours ago









                  Szabolcs

                  157k13430917




                  157k13430917






















                      up vote
                      2
                      down vote













                      You can also Apply (@@@) Sequence at level 1:



                      Sequence @@@ lis



                      "a" | "b" | "c"




                      or use ReplaceAll to replace List with Sequence: 



                      lis /. List -> Sequence



                      "a" | "b" | "c"







                      share|improve this answer



























                        up vote
                        2
                        down vote













                        You can also Apply (@@@) Sequence at level 1:



                        Sequence @@@ lis



                        "a" | "b" | "c"




                        or use ReplaceAll to replace List with Sequence: 



                        lis /. List -> Sequence



                        "a" | "b" | "c"







                        share|improve this answer

























                          up vote
                          2
                          down vote










                          up vote
                          2
                          down vote









                          You can also Apply (@@@) Sequence at level 1:



                          Sequence @@@ lis



                          "a" | "b" | "c"




                          or use ReplaceAll to replace List with Sequence: 



                          lis /. List -> Sequence



                          "a" | "b" | "c"







                          share|improve this answer














                          You can also Apply (@@@) Sequence at level 1:



                          Sequence @@@ lis



                          "a" | "b" | "c"




                          or use ReplaceAll to replace List with Sequence: 



                          lis /. List -> Sequence



                          "a" | "b" | "c"








                          share|improve this answer














                          share|improve this answer



                          share|improve this answer








                          edited 1 hour ago

























                          answered 2 hours ago









                          kglr

                          172k8194399




                          172k8194399






























                               

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