Higher Topos Theory Theorem 2.2.5.3












8














The following question is found in the proof of Theorem 2.2.5.3 of HTT but since it can be understood in a more general context I will just ask it without stating the theorem.



We have a trivial Kan fibration of simplicial sets $p : S rightarrow T$ where $T$ is an $infty$-category. We wish to show that for any two vertices $x,y$ of $S$, the induced map of simplicial sets $$Map_{mathfrak{C}[S]}(x,y) rightarrow Map_{mathfrak{C}[T]}(p(x),p(y))$$ is a Kan weak equivalence.
We have two results, the first one is that the map $$lvert Hom^R_T(p(x),p(y)) rvert_{Q^bullet} rightarrow Map_{mathfrak{C}[T]}(p(x),p(y))$$ where $Q^bullet$ is the cosimplicial object defined in 2.2.2 is a Kan weak equivalence. The second one is that for any simplicial set, the map $$pi_X : lvert X rvert_{Q^bullet} rightarrow X$$ also defined in Section 2.2.2 is also a Kan weak equivalence.
Lurie says that thanks to those two results, it is enough to show that the map $$Hom^R_S(x,y) rightarrow Hom^R_T(p(x),p(y))$$ is a Kan weak equivalence.



I was thinking of fitting all this into a commutative diagram and using the two-out-of-three property but I am struggling with it. Is this the right way to look at it or am I missing something?



If someone needs more definitions I'll gladly add them.










share|cite|improve this question





























    8














    The following question is found in the proof of Theorem 2.2.5.3 of HTT but since it can be understood in a more general context I will just ask it without stating the theorem.



    We have a trivial Kan fibration of simplicial sets $p : S rightarrow T$ where $T$ is an $infty$-category. We wish to show that for any two vertices $x,y$ of $S$, the induced map of simplicial sets $$Map_{mathfrak{C}[S]}(x,y) rightarrow Map_{mathfrak{C}[T]}(p(x),p(y))$$ is a Kan weak equivalence.
    We have two results, the first one is that the map $$lvert Hom^R_T(p(x),p(y)) rvert_{Q^bullet} rightarrow Map_{mathfrak{C}[T]}(p(x),p(y))$$ where $Q^bullet$ is the cosimplicial object defined in 2.2.2 is a Kan weak equivalence. The second one is that for any simplicial set, the map $$pi_X : lvert X rvert_{Q^bullet} rightarrow X$$ also defined in Section 2.2.2 is also a Kan weak equivalence.
    Lurie says that thanks to those two results, it is enough to show that the map $$Hom^R_S(x,y) rightarrow Hom^R_T(p(x),p(y))$$ is a Kan weak equivalence.



    I was thinking of fitting all this into a commutative diagram and using the two-out-of-three property but I am struggling with it. Is this the right way to look at it or am I missing something?



    If someone needs more definitions I'll gladly add them.










    share|cite|improve this question



























      8












      8








      8







      The following question is found in the proof of Theorem 2.2.5.3 of HTT but since it can be understood in a more general context I will just ask it without stating the theorem.



      We have a trivial Kan fibration of simplicial sets $p : S rightarrow T$ where $T$ is an $infty$-category. We wish to show that for any two vertices $x,y$ of $S$, the induced map of simplicial sets $$Map_{mathfrak{C}[S]}(x,y) rightarrow Map_{mathfrak{C}[T]}(p(x),p(y))$$ is a Kan weak equivalence.
      We have two results, the first one is that the map $$lvert Hom^R_T(p(x),p(y)) rvert_{Q^bullet} rightarrow Map_{mathfrak{C}[T]}(p(x),p(y))$$ where $Q^bullet$ is the cosimplicial object defined in 2.2.2 is a Kan weak equivalence. The second one is that for any simplicial set, the map $$pi_X : lvert X rvert_{Q^bullet} rightarrow X$$ also defined in Section 2.2.2 is also a Kan weak equivalence.
      Lurie says that thanks to those two results, it is enough to show that the map $$Hom^R_S(x,y) rightarrow Hom^R_T(p(x),p(y))$$ is a Kan weak equivalence.



      I was thinking of fitting all this into a commutative diagram and using the two-out-of-three property but I am struggling with it. Is this the right way to look at it or am I missing something?



      If someone needs more definitions I'll gladly add them.










      share|cite|improve this question















      The following question is found in the proof of Theorem 2.2.5.3 of HTT but since it can be understood in a more general context I will just ask it without stating the theorem.



      We have a trivial Kan fibration of simplicial sets $p : S rightarrow T$ where $T$ is an $infty$-category. We wish to show that for any two vertices $x,y$ of $S$, the induced map of simplicial sets $$Map_{mathfrak{C}[S]}(x,y) rightarrow Map_{mathfrak{C}[T]}(p(x),p(y))$$ is a Kan weak equivalence.
      We have two results, the first one is that the map $$lvert Hom^R_T(p(x),p(y)) rvert_{Q^bullet} rightarrow Map_{mathfrak{C}[T]}(p(x),p(y))$$ where $Q^bullet$ is the cosimplicial object defined in 2.2.2 is a Kan weak equivalence. The second one is that for any simplicial set, the map $$pi_X : lvert X rvert_{Q^bullet} rightarrow X$$ also defined in Section 2.2.2 is also a Kan weak equivalence.
      Lurie says that thanks to those two results, it is enough to show that the map $$Hom^R_S(x,y) rightarrow Hom^R_T(p(x),p(y))$$ is a Kan weak equivalence.



      I was thinking of fitting all this into a commutative diagram and using the two-out-of-three property but I am struggling with it. Is this the right way to look at it or am I missing something?



      If someone needs more definitions I'll gladly add them.







      ct.category-theory higher-category-theory simplicial-stuff






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited 5 hours ago









      Earthliŋ

      529219




      529219










      asked 10 hours ago









      Valérian Montessuit

      885




      885






















          1 Answer
          1






          active

          oldest

          votes


















          11














          From naturality we have the following commutative diagram:



          $require{AMScd}
          begin{CD}
          Map_{mathfrak C[S]}(x,y) @<sim<< |Hom^R_S(x,y)|_{Q_bullet} @>sim>> Hom^R_S(x,y) \
          @VVV @VVV @VVV\
          Map_{mathfrak C[T]}(px,py) @<sim<< |Hom^R_T(px,py)|_{Q_bullet} @>sim>> Hom^R_T(px,py)
          end{CD}$



          From the above two results the horizontal maps are weak equivalences. So if the right hand vertical map is an equivalence, then by 2/3, so is the middle vertical map, so by 2/3, so is the left hand vertical map.






          share|cite|improve this answer





















            Your Answer





            StackExchange.ifUsing("editor", function () {
            return StackExchange.using("mathjaxEditing", function () {
            StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
            StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
            });
            });
            }, "mathjax-editing");

            StackExchange.ready(function() {
            var channelOptions = {
            tags: "".split(" "),
            id: "504"
            };
            initTagRenderer("".split(" "), "".split(" "), channelOptions);

            StackExchange.using("externalEditor", function() {
            // Have to fire editor after snippets, if snippets enabled
            if (StackExchange.settings.snippets.snippetsEnabled) {
            StackExchange.using("snippets", function() {
            createEditor();
            });
            }
            else {
            createEditor();
            }
            });

            function createEditor() {
            StackExchange.prepareEditor({
            heartbeatType: 'answer',
            autoActivateHeartbeat: false,
            convertImagesToLinks: true,
            noModals: true,
            showLowRepImageUploadWarning: true,
            reputationToPostImages: 10,
            bindNavPrevention: true,
            postfix: "",
            imageUploader: {
            brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
            contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
            allowUrls: true
            },
            noCode: true, onDemand: true,
            discardSelector: ".discard-answer"
            ,immediatelyShowMarkdownHelp:true
            });


            }
            });














            draft saved

            draft discarded


















            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathoverflow.net%2fquestions%2f319513%2fhigher-topos-theory-theorem-2-2-5-3%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown

























            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            11














            From naturality we have the following commutative diagram:



            $require{AMScd}
            begin{CD}
            Map_{mathfrak C[S]}(x,y) @<sim<< |Hom^R_S(x,y)|_{Q_bullet} @>sim>> Hom^R_S(x,y) \
            @VVV @VVV @VVV\
            Map_{mathfrak C[T]}(px,py) @<sim<< |Hom^R_T(px,py)|_{Q_bullet} @>sim>> Hom^R_T(px,py)
            end{CD}$



            From the above two results the horizontal maps are weak equivalences. So if the right hand vertical map is an equivalence, then by 2/3, so is the middle vertical map, so by 2/3, so is the left hand vertical map.






            share|cite|improve this answer


























              11














              From naturality we have the following commutative diagram:



              $require{AMScd}
              begin{CD}
              Map_{mathfrak C[S]}(x,y) @<sim<< |Hom^R_S(x,y)|_{Q_bullet} @>sim>> Hom^R_S(x,y) \
              @VVV @VVV @VVV\
              Map_{mathfrak C[T]}(px,py) @<sim<< |Hom^R_T(px,py)|_{Q_bullet} @>sim>> Hom^R_T(px,py)
              end{CD}$



              From the above two results the horizontal maps are weak equivalences. So if the right hand vertical map is an equivalence, then by 2/3, so is the middle vertical map, so by 2/3, so is the left hand vertical map.






              share|cite|improve this answer
























                11












                11








                11






                From naturality we have the following commutative diagram:



                $require{AMScd}
                begin{CD}
                Map_{mathfrak C[S]}(x,y) @<sim<< |Hom^R_S(x,y)|_{Q_bullet} @>sim>> Hom^R_S(x,y) \
                @VVV @VVV @VVV\
                Map_{mathfrak C[T]}(px,py) @<sim<< |Hom^R_T(px,py)|_{Q_bullet} @>sim>> Hom^R_T(px,py)
                end{CD}$



                From the above two results the horizontal maps are weak equivalences. So if the right hand vertical map is an equivalence, then by 2/3, so is the middle vertical map, so by 2/3, so is the left hand vertical map.






                share|cite|improve this answer












                From naturality we have the following commutative diagram:



                $require{AMScd}
                begin{CD}
                Map_{mathfrak C[S]}(x,y) @<sim<< |Hom^R_S(x,y)|_{Q_bullet} @>sim>> Hom^R_S(x,y) \
                @VVV @VVV @VVV\
                Map_{mathfrak C[T]}(px,py) @<sim<< |Hom^R_T(px,py)|_{Q_bullet} @>sim>> Hom^R_T(px,py)
                end{CD}$



                From the above two results the horizontal maps are weak equivalences. So if the right hand vertical map is an equivalence, then by 2/3, so is the middle vertical map, so by 2/3, so is the left hand vertical map.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered 7 hours ago









                Tim Campion

                13.3k354122




                13.3k354122






























                    draft saved

                    draft discarded




















































                    Thanks for contributing an answer to MathOverflow!


                    • Please be sure to answer the question. Provide details and share your research!

                    But avoid



                    • Asking for help, clarification, or responding to other answers.

                    • Making statements based on opinion; back them up with references or personal experience.


                    Use MathJax to format equations. MathJax reference.


                    To learn more, see our tips on writing great answers.





                    Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


                    Please pay close attention to the following guidance:


                    • Please be sure to answer the question. Provide details and share your research!

                    But avoid



                    • Asking for help, clarification, or responding to other answers.

                    • Making statements based on opinion; back them up with references or personal experience.


                    To learn more, see our tips on writing great answers.




                    draft saved


                    draft discarded














                    StackExchange.ready(
                    function () {
                    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathoverflow.net%2fquestions%2f319513%2fhigher-topos-theory-theorem-2-2-5-3%23new-answer', 'question_page');
                    }
                    );

                    Post as a guest















                    Required, but never shown





















































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown

































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown







                    Popular posts from this blog

                    Trompette piccolo

                    Slow SSRS Report in dynamic grouping and multiple parameters

                    Simon Yates (cyclisme)