Check if an input is equal to any item in the list [duplicate]












0















This question already has an answer here:




  • Fastest way to check if a value exist in a list

    12 answers




let's say we have a list



a=["a1", "a2", "a3"]


then we have an input:



x=input("enter something: ")


how would you check if that input "x" is equal to any item in the list and then return true?






python







share|improve this question













marked as duplicate by slider, quamrana, Austin, Rahul K P, Mr. T Nov 22 at 20:09


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.















  • You can do if x in a: return True.
    – slider
    Nov 22 at 18:06










  • it is not a duplicate of that article as i have a different situation
    – Coder Cody
    Nov 22 at 18:12










  • How is it different? Can you be more specific?
    – slider
    Nov 22 at 18:14










  • I didn't really want to disclose this information but I'm trying to make a naughts and crosses game and I've created lists to hold the data of each square in the naughts and crosses. I will then ask for an input and use that input, not to count how many times it repeats but use it to simply see whether the input correlates to a keyword to describe each square. I just did not find my answer on that particular post
    – Coder Cody
    Nov 22 at 18:17






  • 1




    @slider Just x in a will do the trick.
    – Klaus D.
    Nov 22 at 19:11
















0















This question already has an answer here:




  • Fastest way to check if a value exist in a list

    12 answers




let's say we have a list



a=["a1", "a2", "a3"]


then we have an input:



x=input("enter something: ")


how would you check if that input "x" is equal to any item in the list and then return true?






python







share|improve this question













marked as duplicate by slider, quamrana, Austin, Rahul K P, Mr. T Nov 22 at 20:09


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.















  • You can do if x in a: return True.
    – slider
    Nov 22 at 18:06










  • it is not a duplicate of that article as i have a different situation
    – Coder Cody
    Nov 22 at 18:12










  • How is it different? Can you be more specific?
    – slider
    Nov 22 at 18:14










  • I didn't really want to disclose this information but I'm trying to make a naughts and crosses game and I've created lists to hold the data of each square in the naughts and crosses. I will then ask for an input and use that input, not to count how many times it repeats but use it to simply see whether the input correlates to a keyword to describe each square. I just did not find my answer on that particular post
    – Coder Cody
    Nov 22 at 18:17






  • 1




    @slider Just x in a will do the trick.
    – Klaus D.
    Nov 22 at 19:11














0












0








0








This question already has an answer here:




  • Fastest way to check if a value exist in a list

    12 answers




let's say we have a list



a=["a1", "a2", "a3"]


then we have an input:



x=input("enter something: ")


how would you check if that input "x" is equal to any item in the list and then return true?






python







share|improve this question














This question already has an answer here:




  • Fastest way to check if a value exist in a list

    12 answers




let's say we have a list



a=["a1", "a2", "a3"]


then we have an input:



x=input("enter something: ")


how would you check if that input "x" is equal to any item in the list and then return true?





This question already has an answer here:




  • Fastest way to check if a value exist in a list

    12 answers







python




python






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 22 at 18:05









Coder Cody

408




408




marked as duplicate by slider, quamrana, Austin, Rahul K P, Mr. T Nov 22 at 20:09


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.






marked as duplicate by slider, quamrana, Austin, Rahul K P, Mr. T Nov 22 at 20:09


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.














  • You can do if x in a: return True.
    – slider
    Nov 22 at 18:06










  • it is not a duplicate of that article as i have a different situation
    – Coder Cody
    Nov 22 at 18:12










  • How is it different? Can you be more specific?
    – slider
    Nov 22 at 18:14










  • I didn't really want to disclose this information but I'm trying to make a naughts and crosses game and I've created lists to hold the data of each square in the naughts and crosses. I will then ask for an input and use that input, not to count how many times it repeats but use it to simply see whether the input correlates to a keyword to describe each square. I just did not find my answer on that particular post
    – Coder Cody
    Nov 22 at 18:17






  • 1




    @slider Just x in a will do the trick.
    – Klaus D.
    Nov 22 at 19:11


















  • You can do if x in a: return True.
    – slider
    Nov 22 at 18:06










  • it is not a duplicate of that article as i have a different situation
    – Coder Cody
    Nov 22 at 18:12










  • How is it different? Can you be more specific?
    – slider
    Nov 22 at 18:14










  • I didn't really want to disclose this information but I'm trying to make a naughts and crosses game and I've created lists to hold the data of each square in the naughts and crosses. I will then ask for an input and use that input, not to count how many times it repeats but use it to simply see whether the input correlates to a keyword to describe each square. I just did not find my answer on that particular post
    – Coder Cody
    Nov 22 at 18:17






  • 1




    @slider Just x in a will do the trick.
    – Klaus D.
    Nov 22 at 19:11
















You can do if x in a: return True.
– slider
Nov 22 at 18:06




You can do if x in a: return True.
– slider
Nov 22 at 18:06












it is not a duplicate of that article as i have a different situation
– Coder Cody
Nov 22 at 18:12




it is not a duplicate of that article as i have a different situation
– Coder Cody
Nov 22 at 18:12












How is it different? Can you be more specific?
– slider
Nov 22 at 18:14




How is it different? Can you be more specific?
– slider
Nov 22 at 18:14












I didn't really want to disclose this information but I'm trying to make a naughts and crosses game and I've created lists to hold the data of each square in the naughts and crosses. I will then ask for an input and use that input, not to count how many times it repeats but use it to simply see whether the input correlates to a keyword to describe each square. I just did not find my answer on that particular post
– Coder Cody
Nov 22 at 18:17




I didn't really want to disclose this information but I'm trying to make a naughts and crosses game and I've created lists to hold the data of each square in the naughts and crosses. I will then ask for an input and use that input, not to count how many times it repeats but use it to simply see whether the input correlates to a keyword to describe each square. I just did not find my answer on that particular post
– Coder Cody
Nov 22 at 18:17




1




1




@slider Just x in a will do the trick.
– Klaus D.
Nov 22 at 19:11




@slider Just x in a will do the trick.
– Klaus D.
Nov 22 at 19:11












1 Answer
1






active

oldest

votes


















1














You can check it with that code:



print("Yes, x in list" if x in a else "No, x is not in list")


It same that:



if x in a:

    print("Yes, x in list")

else:

    print("No, x is not in list")


Also if you want to get index of contained element - just use .index(): 



if x in a: 

    print('Yes, x in list, and it index is:', a.index(x))


In that example i'am avoid else: construct, but you can use it like in previous example, if you need it.






share|improve this answer






























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    You can check it with that code:



    print("Yes, x in list" if x in a else "No, x is not in list")


    It same that:



    if x in a:
    
    print("Yes, x in list")
    
else:
    
    print("No, x is not in list")


    Also if you want to get index of contained element - just use .index(): 



    if x in a: 
    
    print('Yes, x in list, and it index is:', a.index(x))


    In that example i'am avoid else: construct, but you can use it like in previous example, if you need it.






    share|improve this answer




























      1














      You can check it with that code:



      print("Yes, x in list" if x in a else "No, x is not in list")


      It same that:



      if x in a:
      
    print("Yes, x in list")
      
else:
      
    print("No, x is not in list")


      Also if you want to get index of contained element - just use .index(): 



      if x in a: 
      
    print('Yes, x in list, and it index is:', a.index(x))


      In that example i'am avoid else: construct, but you can use it like in previous example, if you need it.






      share|improve this answer


























        1












        1








        1






        You can check it with that code:



        print("Yes, x in list" if x in a else "No, x is not in list")


        It same that:



        if x in a:
        
    print("Yes, x in list")
        
else:
        
    print("No, x is not in list")


        Also if you want to get index of contained element - just use .index(): 



        if x in a: 
        
    print('Yes, x in list, and it index is:', a.index(x))


        In that example i'am avoid else: construct, but you can use it like in previous example, if you need it.






        share|improve this answer














        You can check it with that code:



        print("Yes, x in list" if x in a else "No, x is not in list")


        It same that:



        if x in a:
        
    print("Yes, x in list")
        
else:
        
    print("No, x is not in list")


        Also if you want to get index of contained element - just use .index(): 



        if x in a: 
        
    print('Yes, x in list, and it index is:', a.index(x))


        In that example i'am avoid else: construct, but you can use it like in previous example, if you need it.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 22 at 18:24

























        answered Nov 22 at 18:12









        Andrey Suglobov

        1248




        1248















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