basic java net client returns 400

The following code has been copied out for Horstmann's, Big Java Early Objects 6th edition - Chapter 23.3. The only modification is the package, added by eclipse.

The code:

package zipCodeScrapper;

import java.io.InputStream;

import java.io.IOException;

import java.io.OutputStream;

import java.io.PrintWriter;

import java.net.Socket;

import java.util.Scanner;



public class client {

    public static void main(String args) throws IOException {

        // Get command-line arguments

        String host;

        String resource;



        if (args.length == 2) {

            host = args[0];

            resource = args[1];

        } else {

            System.out.println("Getting / from horstmann.com");

            host = "horstmann.com";

            resource = "/";

        }



        // Open socket

        final int HTTP_PORT = 80;

        try (Socket s = new Socket(host, HTTP_PORT)) {



            // Get streams

            InputStream instream = s.getInputStream();

            OutputStream outstream = s.getOutputStream();



            // Turn streams into scanners and writers

            Scanner in = new Scanner(instream);

            PrintWriter out = new PrintWriter(outstream);



            // Send command

            String command = "GET " + resource + " HTTP/1.1n" + "Host: " + host + "nn";

            out.print(command);

            out.flush();



            while (in.hasNextLine()) {

                String input = in.nextLine();

                System.out.println(input);

            }

        }

    }

}

The code receives a 400 Bad Request. I have tried replacing the host and resources with other values, however I continue to get error 400.

asked Nov 23 '18 at 6:59

Alexander McNulty

349214

1

The line terminator in HTTP is defined as rn, not just n.
– user207421
Nov 23 '18 at 7:04

add a comment |

The following code has been copied out for Horstmann's, Big Java Early Objects 6th edition - Chapter 23.3. The only modification is the package, added by eclipse.

The code:

package zipCodeScrapper;

import java.io.InputStream;

import java.io.IOException;

import java.io.OutputStream;

import java.io.PrintWriter;

import java.net.Socket;

import java.util.Scanner;



public class client {

    public static void main(String args) throws IOException {

        // Get command-line arguments

        String host;

        String resource;



        if (args.length == 2) {

            host = args[0];

            resource = args[1];

        } else {

            System.out.println("Getting / from horstmann.com");

            host = "horstmann.com";

            resource = "/";

        }



        // Open socket

        final int HTTP_PORT = 80;

        try (Socket s = new Socket(host, HTTP_PORT)) {



            // Get streams

            InputStream instream = s.getInputStream();

            OutputStream outstream = s.getOutputStream();



            // Turn streams into scanners and writers

            Scanner in = new Scanner(instream);

            PrintWriter out = new PrintWriter(outstream);



            // Send command

            String command = "GET " + resource + " HTTP/1.1n" + "Host: " + host + "nn";

            out.print(command);

            out.flush();



            while (in.hasNextLine()) {

                String input = in.nextLine();

                System.out.println(input);

            }

        }

    }

}

The code receives a 400 Bad Request. I have tried replacing the host and resources with other values, however I continue to get error 400.

asked Nov 23 '18 at 6:59

Alexander McNulty

349214

1

The line terminator in HTTP is defined as rn, not just n.
– user207421
Nov 23 '18 at 7:04

add a comment |

The following code has been copied out for Horstmann's, Big Java Early Objects 6th edition - Chapter 23.3. The only modification is the package, added by eclipse.

The code:

package zipCodeScrapper;

import java.io.InputStream;

import java.io.IOException;

import java.io.OutputStream;

import java.io.PrintWriter;

import java.net.Socket;

import java.util.Scanner;



public class client {

    public static void main(String args) throws IOException {

        // Get command-line arguments

        String host;

        String resource;



        if (args.length == 2) {

            host = args[0];

            resource = args[1];

        } else {

            System.out.println("Getting / from horstmann.com");

            host = "horstmann.com";

            resource = "/";

        }



        // Open socket

        final int HTTP_PORT = 80;

        try (Socket s = new Socket(host, HTTP_PORT)) {



            // Get streams

            InputStream instream = s.getInputStream();

            OutputStream outstream = s.getOutputStream();



            // Turn streams into scanners and writers

            Scanner in = new Scanner(instream);

            PrintWriter out = new PrintWriter(outstream);



            // Send command

            String command = "GET " + resource + " HTTP/1.1n" + "Host: " + host + "nn";

            out.print(command);

            out.flush();



            while (in.hasNextLine()) {

                String input = in.nextLine();

                System.out.println(input);

            }

        }

    }

}

The code receives a 400 Bad Request. I have tried replacing the host and resources with other values, however I continue to get error 400.

asked Nov 23 '18 at 6:59

Alexander McNulty

349214

The following code has been copied out for Horstmann's, Big Java Early Objects 6th edition - Chapter 23.3. The only modification is the package, added by eclipse.

The code:

package zipCodeScrapper;

import java.io.InputStream;

import java.io.IOException;

import java.io.OutputStream;

import java.io.PrintWriter;

import java.net.Socket;

import java.util.Scanner;



public class client {

    public static void main(String args) throws IOException {

        // Get command-line arguments

        String host;

        String resource;



        if (args.length == 2) {

            host = args[0];

            resource = args[1];

        } else {

            System.out.println("Getting / from horstmann.com");

            host = "horstmann.com";

            resource = "/";

        }



        // Open socket

        final int HTTP_PORT = 80;

        try (Socket s = new Socket(host, HTTP_PORT)) {



            // Get streams

            InputStream instream = s.getInputStream();

            OutputStream outstream = s.getOutputStream();



            // Turn streams into scanners and writers

            Scanner in = new Scanner(instream);

            PrintWriter out = new PrintWriter(outstream);



            // Send command

            String command = "GET " + resource + " HTTP/1.1n" + "Host: " + host + "nn";

            out.print(command);

            out.flush();



            while (in.hasNextLine()) {

                String input = in.nextLine();

                System.out.println(input);

            }

        }

    }

}

The code receives a 400 Bad Request. I have tried replacing the host and resources with other values, however I continue to get error 400.

java sockets http-status-code-400

asked Nov 23 '18 at 6:59

Alexander McNulty

349214

asked Nov 23 '18 at 6:59

Alexander McNulty

349214

asked Nov 23 '18 at 6:59

Alexander McNulty

349214

asked Nov 23 '18 at 6:59

Alexander McNulty

349214

asked Nov 23 '18 at 6:59

Alexander McNulty

349214

1

The line terminator in HTTP is defined as rn, not just n.
– user207421
Nov 23 '18 at 7:04

add a comment |

1

The line terminator in HTTP is defined as rn, not just n.
– user207421
Nov 23 '18 at 7:04

The line terminator in HTTP is defined as rn, not just n.
– user207421
Nov 23 '18 at 7:04

add a comment |

1 Answer
1

active

oldest

votes

Firstly , read this documentations. RFC p1 and RFC2 p2

Line separator of HTTP is not a n . It must be rn . For more read this thread ;

What is line breaker in HTTP?

answered Nov 23 '18 at 7:09

drowny

1,605314

in case this isn't clear to anyone who has the same problem, every n in my "command" string should be replace by rn
– Alexander McNulty
Nov 23 '18 at 7:21

thanks for the answer, and +1 for the suggested reading.
– Alexander McNulty
Nov 23 '18 at 7:22

add a comment |

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1 Answer
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active

oldest

votes

1 Answer
1

active

oldest

votes

Firstly , read this documentations. RFC p1 and RFC2 p2

Line separator of HTTP is not a n . It must be rn . For more read this thread ;

What is line breaker in HTTP?

answered Nov 23 '18 at 7:09

drowny

1,605314

in case this isn't clear to anyone who has the same problem, every n in my "command" string should be replace by rn
– Alexander McNulty
Nov 23 '18 at 7:21

thanks for the answer, and +1 for the suggested reading.
– Alexander McNulty
Nov 23 '18 at 7:22

add a comment |

Firstly , read this documentations. RFC p1 and RFC2 p2

Line separator of HTTP is not a n . It must be rn . For more read this thread ;

What is line breaker in HTTP?

answered Nov 23 '18 at 7:09

drowny

1,605314

in case this isn't clear to anyone who has the same problem, every n in my "command" string should be replace by rn
– Alexander McNulty
Nov 23 '18 at 7:21

thanks for the answer, and +1 for the suggested reading.
– Alexander McNulty
Nov 23 '18 at 7:22

add a comment |

Firstly , read this documentations. RFC p1 and RFC2 p2

Line separator of HTTP is not a n . It must be rn . For more read this thread ;

What is line breaker in HTTP?

answered Nov 23 '18 at 7:09

drowny

1,605314

Firstly , read this documentations. RFC p1 and RFC2 p2

Line separator of HTTP is not a n . It must be rn . For more read this thread ;

What is line breaker in HTTP?

answered Nov 23 '18 at 7:09

drowny

1,605314

answered Nov 23 '18 at 7:09

drowny

1,605314

answered Nov 23 '18 at 7:09

drowny

1,605314

answered Nov 23 '18 at 7:09

drowny

1,605314

in case this isn't clear to anyone who has the same problem, every n in my "command" string should be replace by rn
– Alexander McNulty
Nov 23 '18 at 7:21

thanks for the answer, and +1 for the suggested reading.
– Alexander McNulty
Nov 23 '18 at 7:22

add a comment |

in case this isn't clear to anyone who has the same problem, every n in my "command" string should be replace by rn
– Alexander McNulty
Nov 23 '18 at 7:21

thanks for the answer, and +1 for the suggested reading.
– Alexander McNulty
Nov 23 '18 at 7:22

in case this isn't clear to anyone who has the same problem, every n in my "command" string should be replace by rn
– Alexander McNulty
Nov 23 '18 at 7:21

thanks for the answer, and +1 for the suggested reading.
– Alexander McNulty
Nov 23 '18 at 7:22

add a comment |

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