Calling another returned function in the same module
up vote
0
down vote
favorite
I have a module like this:
var myMod = function() {
return {
f_a: function() {}
f_b: function() {}
}
})();
I need to call f_b from f_a, and I do not know what is the best way to do this.
javascript module
asked Nov 22 at 16:56
Giacomo Masseroni Chiaro
386315
add a comment |
up vote
0
down vote
favorite
I have a module like this:
var myMod = function() {
return {
f_a: function() {}
f_b: function() {}
}
})();
I need to call f_b from f_a, and I do not know what is the best way to do this.
javascript module
asked Nov 22 at 16:56
Giacomo Masseroni Chiaro
386315
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have a module like this:
var myMod = function() {
return {
f_a: function() {}
f_b: function() {}
}
})();
I need to call f_b from f_a, and I do not know what is the best way to do this.
javascript module
asked Nov 22 at 16:56
Giacomo Masseroni Chiaro
386315
I have a module like this:
var myMod = function() {
return {
f_a: function() {}
f_b: function() {}
}
})();
I need to call f_b from f_a, and I do not know what is the best way to do this.
javascript module
javascript module
asked Nov 22 at 16:56
Giacomo Masseroni Chiaro
386315
asked Nov 22 at 16:56
Giacomo Masseroni Chiaro
386315
asked Nov 22 at 16:56
Giacomo Masseroni Chiaro
386315
asked Nov 22 at 16:56
Giacomo Masseroni Chiaro
386315
asked Nov 22 at 16:56
Giacomo Masseroni Chiaro
386315
386315
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
up vote
1
down vote
accepted
var myMod = (function() {
return {
f_a: function() {console.log('hi from f_a');},
f_b: function() {this.f_a();}
}
})();
myMod.f_b();You can do it like this
var myMod = (function() {
return {
f_a: function() {console.log('hi from f_a');},
f_b: function() {this.f_a();}
}
})();
myMod.f_b();
answered Nov 22 at 17:06
Salih Şenol Çakarcı
1,709719
I get this.f_a() is not a function error
– Giacomo Masseroni Chiaro
Nov 22 at 17:09
actually you can run the code snippet above it is working maybe some syntax error you have please copy the above code and try again
– Salih Şenol Çakarcı
Nov 22 at 17:17
Is the order of the function declarations considerable?
– Giacomo Masseroni Chiaro
Nov 22 at 17:22
yes you need to call myMod after declaration
– Salih Şenol Çakarcı
Nov 22 at 17:23
I mean f_a and f_b. Can I declare f_a before f_b and then call f_b from f_a?
– Giacomo Masseroni Chiaro
Nov 22 at 17:28
add a comment |
up vote
1
down vote
There is an extra )().It seems you want create an immediately invoking function expression.
var myMod = function() {
return {
f_a: function() {
console.log('f_a')
},
f_b: function() {
console.log('f_b');
}
}
};
console.log(myMod().f_a())If you want to call f_b from f_b then use this.Actually if you see correctly it this function is returning an object. In javascript inside an object to refer to it's property using this
var myMod = function() {
return {
f_a: function() {
console.log('f_a')
},
f_b: function() {
this.f_a();
console.log('f_b');
}
}
};
console.log(myMod().f_b())answered Nov 22 at 17:01
brk
25.2k31939
Thanks, but what about calling f_b from f_a inside the module?
– Giacomo Masseroni Chiaro
Nov 22 at 17:05
do you mean to callf_afromf_b?
– brk
Nov 22 at 17:06
Yes. I need to call f_a from f_b or viceversa
– Giacomo Masseroni Chiaro
Nov 22 at 17:10
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
var myMod = (function() {
return {
f_a: function() {console.log('hi from f_a');},
f_b: function() {this.f_a();}
}
})();
myMod.f_b();You can do it like this
var myMod = (function() {
return {
f_a: function() {console.log('hi from f_a');},
f_b: function() {this.f_a();}
}
})();
myMod.f_b();
answered Nov 22 at 17:06
Salih Şenol Çakarcı
1,709719
I get this.f_a() is not a function error
– Giacomo Masseroni Chiaro
Nov 22 at 17:09
actually you can run the code snippet above it is working maybe some syntax error you have please copy the above code and try again
– Salih Şenol Çakarcı
Nov 22 at 17:17
Is the order of the function declarations considerable?
– Giacomo Masseroni Chiaro
Nov 22 at 17:22
yes you need to call myMod after declaration
– Salih Şenol Çakarcı
Nov 22 at 17:23
I mean f_a and f_b. Can I declare f_a before f_b and then call f_b from f_a?
– Giacomo Masseroni Chiaro
Nov 22 at 17:28
add a comment |
up vote
1
down vote
accepted
var myMod = (function() {
return {
f_a: function() {console.log('hi from f_a');},
f_b: function() {this.f_a();}
}
})();
myMod.f_b();You can do it like this
var myMod = (function() {
return {
f_a: function() {console.log('hi from f_a');},
f_b: function() {this.f_a();}
}
})();
myMod.f_b();
answered Nov 22 at 17:06
Salih Şenol Çakarcı
1,709719
I get this.f_a() is not a function error
– Giacomo Masseroni Chiaro
Nov 22 at 17:09
actually you can run the code snippet above it is working maybe some syntax error you have please copy the above code and try again
– Salih Şenol Çakarcı
Nov 22 at 17:17
Is the order of the function declarations considerable?
– Giacomo Masseroni Chiaro
Nov 22 at 17:22
yes you need to call myMod after declaration
– Salih Şenol Çakarcı
Nov 22 at 17:23
I mean f_a and f_b. Can I declare f_a before f_b and then call f_b from f_a?
– Giacomo Masseroni Chiaro
Nov 22 at 17:28
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
var myMod = (function() {
return {
f_a: function() {console.log('hi from f_a');},
f_b: function() {this.f_a();}
}
})();
myMod.f_b();You can do it like this
var myMod = (function() {
return {
f_a: function() {console.log('hi from f_a');},
f_b: function() {this.f_a();}
}
})();
myMod.f_b();
answered Nov 22 at 17:06
Salih Şenol Çakarcı
1,709719
var myMod = (function() {
return {
f_a: function() {console.log('hi from f_a');},
f_b: function() {this.f_a();}
}
})();
myMod.f_b();You can do it like this
var myMod = (function() {
return {
f_a: function() {console.log('hi from f_a');},
f_b: function() {this.f_a();}
}
})();
myMod.f_b();
var myMod = (function() {
return {
f_a: function() {console.log('hi from f_a');},
f_b: function() {this.f_a();}
}
})();
myMod.f_b();var myMod = (function() {
return {
f_a: function() {console.log('hi from f_a');},
f_b: function() {this.f_a();}
}
})();
myMod.f_b();answered Nov 22 at 17:06
Salih Şenol Çakarcı
1,709719
answered Nov 22 at 17:06
Salih Şenol Çakarcı
1,709719
answered Nov 22 at 17:06
Salih Şenol Çakarcı
1,709719
answered Nov 22 at 17:06
Salih Şenol Çakarcı
1,709719
1,709719
I get this.f_a() is not a function error
– Giacomo Masseroni Chiaro
Nov 22 at 17:09
actually you can run the code snippet above it is working maybe some syntax error you have please copy the above code and try again
– Salih Şenol Çakarcı
Nov 22 at 17:17
Is the order of the function declarations considerable?
– Giacomo Masseroni Chiaro
Nov 22 at 17:22
yes you need to call myMod after declaration
– Salih Şenol Çakarcı
Nov 22 at 17:23
I mean f_a and f_b. Can I declare f_a before f_b and then call f_b from f_a?
– Giacomo Masseroni Chiaro
Nov 22 at 17:28
add a comment |
I get this.f_a() is not a function error
– Giacomo Masseroni Chiaro
Nov 22 at 17:09
actually you can run the code snippet above it is working maybe some syntax error you have please copy the above code and try again
– Salih Şenol Çakarcı
Nov 22 at 17:17
Is the order of the function declarations considerable?
– Giacomo Masseroni Chiaro
Nov 22 at 17:22
yes you need to call myMod after declaration
– Salih Şenol Çakarcı
Nov 22 at 17:23
I mean f_a and f_b. Can I declare f_a before f_b and then call f_b from f_a?
– Giacomo Masseroni Chiaro
Nov 22 at 17:28
I get this.f_a() is not a function error
– Giacomo Masseroni Chiaro
Nov 22 at 17:09
I get this.f_a() is not a function error
– Giacomo Masseroni Chiaro
Nov 22 at 17:09
actually you can run the code snippet above it is working maybe some syntax error you have please copy the above code and try again
– Salih Şenol Çakarcı
Nov 22 at 17:17
actually you can run the code snippet above it is working maybe some syntax error you have please copy the above code and try again
– Salih Şenol Çakarcı
Nov 22 at 17:17
Is the order of the function declarations considerable?
– Giacomo Masseroni Chiaro
Nov 22 at 17:22
Is the order of the function declarations considerable?
– Giacomo Masseroni Chiaro
Nov 22 at 17:22
yes you need to call myMod after declaration
– Salih Şenol Çakarcı
Nov 22 at 17:23
yes you need to call myMod after declaration
– Salih Şenol Çakarcı
Nov 22 at 17:23
I mean f_a and f_b. Can I declare f_a before f_b and then call f_b from f_a?
– Giacomo Masseroni Chiaro
Nov 22 at 17:28
I mean f_a and f_b. Can I declare f_a before f_b and then call f_b from f_a?
– Giacomo Masseroni Chiaro
Nov 22 at 17:28
add a comment |
up vote
1
down vote
There is an extra )().It seems you want create an immediately invoking function expression.
var myMod = function() {
return {
f_a: function() {
console.log('f_a')
},
f_b: function() {
console.log('f_b');
}
}
};
console.log(myMod().f_a())If you want to call f_b from f_b then use this.Actually if you see correctly it this function is returning an object. In javascript inside an object to refer to it's property using this
var myMod = function() {
return {
f_a: function() {
console.log('f_a')
},
f_b: function() {
this.f_a();
console.log('f_b');
}
}
};
console.log(myMod().f_b())answered Nov 22 at 17:01
brk
25.2k31939
Thanks, but what about calling f_b from f_a inside the module?
– Giacomo Masseroni Chiaro
Nov 22 at 17:05
do you mean to callf_afromf_b?
– brk
Nov 22 at 17:06
Yes. I need to call f_a from f_b or viceversa
– Giacomo Masseroni Chiaro
Nov 22 at 17:10
add a comment |
up vote
1
down vote
There is an extra )().It seems you want create an immediately invoking function expression.
var myMod = function() {
return {
f_a: function() {
console.log('f_a')
},
f_b: function() {
console.log('f_b');
}
}
};
console.log(myMod().f_a())If you want to call f_b from f_b then use this.Actually if you see correctly it this function is returning an object. In javascript inside an object to refer to it's property using this
var myMod = function() {
return {
f_a: function() {
console.log('f_a')
},
f_b: function() {
this.f_a();
console.log('f_b');
}
}
};
console.log(myMod().f_b())answered Nov 22 at 17:01
brk
25.2k31939
Thanks, but what about calling f_b from f_a inside the module?
– Giacomo Masseroni Chiaro
Nov 22 at 17:05
do you mean to callf_afromf_b?
– brk
Nov 22 at 17:06
Yes. I need to call f_a from f_b or viceversa
– Giacomo Masseroni Chiaro
Nov 22 at 17:10
add a comment |
up vote
1
down vote
up vote
1
down vote
There is an extra )().It seems you want create an immediately invoking function expression.
var myMod = function() {
return {
f_a: function() {
console.log('f_a')
},
f_b: function() {
console.log('f_b');
}
}
};
console.log(myMod().f_a())If you want to call f_b from f_b then use this.Actually if you see correctly it this function is returning an object. In javascript inside an object to refer to it's property using this
var myMod = function() {
return {
f_a: function() {
console.log('f_a')
},
f_b: function() {
this.f_a();
console.log('f_b');
}
}
};
console.log(myMod().f_b())answered Nov 22 at 17:01
brk
25.2k31939
There is an extra )().It seems you want create an immediately invoking function expression.
var myMod = function() {
return {
f_a: function() {
console.log('f_a')
},
f_b: function() {
console.log('f_b');
}
}
};
console.log(myMod().f_a())If you want to call f_b from f_b then use this.Actually if you see correctly it this function is returning an object. In javascript inside an object to refer to it's property using this
var myMod = function() {
return {
f_a: function() {
console.log('f_a')
},
f_b: function() {
this.f_a();
console.log('f_b');
}
}
};
console.log(myMod().f_b())var myMod = function() {
return {
f_a: function() {
console.log('f_a')
},
f_b: function() {
console.log('f_b');
}
}
};
console.log(myMod().f_a())var myMod = function() {
return {
f_a: function() {
console.log('f_a')
},
f_b: function() {
console.log('f_b');
}
}
};
console.log(myMod().f_a())var myMod = function() {
return {
f_a: function() {
console.log('f_a')
},
f_b: function() {
this.f_a();
console.log('f_b');
}
}
};
console.log(myMod().f_b())var myMod = function() {
return {
f_a: function() {
console.log('f_a')
},
f_b: function() {
this.f_a();
console.log('f_b');
}
}
};
console.log(myMod().f_b())answered Nov 22 at 17:01
brk
25.2k31939
edited Nov 22 at 17:12
answered Nov 22 at 17:01
brk
25.2k31939
answered Nov 22 at 17:01
brk
25.2k31939
answered Nov 22 at 17:01
brk
25.2k31939
25.2k31939
Thanks, but what about calling f_b from f_a inside the module?
– Giacomo Masseroni Chiaro
Nov 22 at 17:05
do you mean to callf_afromf_b?
– brk
Nov 22 at 17:06
Yes. I need to call f_a from f_b or viceversa
– Giacomo Masseroni Chiaro
Nov 22 at 17:10
add a comment |
Thanks, but what about calling f_b from f_a inside the module?
– Giacomo Masseroni Chiaro
Nov 22 at 17:05
do you mean to callf_afromf_b?
– brk
Nov 22 at 17:06
Yes. I need to call f_a from f_b or viceversa
– Giacomo Masseroni Chiaro
Nov 22 at 17:10
Thanks, but what about calling f_b from f_a inside the module?
– Giacomo Masseroni Chiaro
Nov 22 at 17:05
Thanks, but what about calling f_b from f_a inside the module?
– Giacomo Masseroni Chiaro
Nov 22 at 17:05
do you mean to call
f_a from f_b?– brk
Nov 22 at 17:06
do you mean to call
f_a from f_b?– brk
Nov 22 at 17:06
Yes. I need to call f_a from f_b or viceversa
– Giacomo Masseroni Chiaro
Nov 22 at 17:10
Yes. I need to call f_a from f_b or viceversa
– Giacomo Masseroni Chiaro
Nov 22 at 17:10
add a comment |
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