Updating textbox.text value when executing code
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If i use: Label1.Invoke(Sub() Label1.Text = "Test") this updates successfully however, if i try do: Txt_Response.Invoke(Sub() Txt_Response.Text = "Test") the text only updates after the rest of the code has executed and the thread is free.
Is there an easy way to accomplish this without any extra load?
vb.net multithreading
asked Nov 22 at 9:52
William
72
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up vote
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If i use: Label1.Invoke(Sub() Label1.Text = "Test") this updates successfully however, if i try do: Txt_Response.Invoke(Sub() Txt_Response.Text = "Test") the text only updates after the rest of the code has executed and the thread is free.
Is there an easy way to accomplish this without any extra load?
vb.net multithreading
asked Nov 22 at 9:52
William
72
I'm not seeing that behaviour. In my test, both controls reflected the change when it was made. I just had aThread.Sleepcall before and after the invocations. What else are you doing?
– jmcilhinney
Nov 22 at 11:31
Control.Invoke() in synchronous. If it doesn't raise an exception, then the request has been fulfilled and the control's property has been updated. It doesn't mean that the UI had the chance to re-drawn itself. Try with BeginInvoke(), the asynchronous version (which also works when the thread is actually the same thread where the code is executed).
– Jimi
Nov 22 at 13:50
I am running a bunch of other operations for connecting to a COM Port and pushing commands down the pipe. So my aim was to show progress of everything as its doing all that. Seemed to have failed doing the easy way..
– William
Nov 22 at 15:00
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
If i use: Label1.Invoke(Sub() Label1.Text = "Test") this updates successfully however, if i try do: Txt_Response.Invoke(Sub() Txt_Response.Text = "Test") the text only updates after the rest of the code has executed and the thread is free.
Is there an easy way to accomplish this without any extra load?
vb.net multithreading
asked Nov 22 at 9:52
William
72
If i use: Label1.Invoke(Sub() Label1.Text = "Test") this updates successfully however, if i try do: Txt_Response.Invoke(Sub() Txt_Response.Text = "Test") the text only updates after the rest of the code has executed and the thread is free.
Is there an easy way to accomplish this without any extra load?
vb.net multithreading
vb.net multithreading
asked Nov 22 at 9:52
William
72
asked Nov 22 at 9:52
William
72
asked Nov 22 at 9:52
William
72
asked Nov 22 at 9:52
William
72
asked Nov 22 at 9:52
William
72
72
I'm not seeing that behaviour. In my test, both controls reflected the change when it was made. I just had aThread.Sleepcall before and after the invocations. What else are you doing?
– jmcilhinney
Nov 22 at 11:31
Control.Invoke() in synchronous. If it doesn't raise an exception, then the request has been fulfilled and the control's property has been updated. It doesn't mean that the UI had the chance to re-drawn itself. Try with BeginInvoke(), the asynchronous version (which also works when the thread is actually the same thread where the code is executed).
– Jimi
Nov 22 at 13:50
I am running a bunch of other operations for connecting to a COM Port and pushing commands down the pipe. So my aim was to show progress of everything as its doing all that. Seemed to have failed doing the easy way..
– William
Nov 22 at 15:00
add a comment |
I'm not seeing that behaviour. In my test, both controls reflected the change when it was made. I just had aThread.Sleepcall before and after the invocations. What else are you doing?
– jmcilhinney
Nov 22 at 11:31
Control.Invoke() in synchronous. If it doesn't raise an exception, then the request has been fulfilled and the control's property has been updated. It doesn't mean that the UI had the chance to re-drawn itself. Try with BeginInvoke(), the asynchronous version (which also works when the thread is actually the same thread where the code is executed).
– Jimi
Nov 22 at 13:50
I am running a bunch of other operations for connecting to a COM Port and pushing commands down the pipe. So my aim was to show progress of everything as its doing all that. Seemed to have failed doing the easy way..
– William
Nov 22 at 15:00
I'm not seeing that behaviour. In my test, both controls reflected the change when it was made. I just had a
Thread.Sleep call before and after the invocations. What else are you doing?– jmcilhinney
Nov 22 at 11:31
I'm not seeing that behaviour. In my test, both controls reflected the change when it was made. I just had a
Thread.Sleep call before and after the invocations. What else are you doing?– jmcilhinney
Nov 22 at 11:31
Control.Invoke() in synchronous. If it doesn't raise an exception, then the request has been fulfilled and the control's property has been updated. It doesn't mean that the UI had the chance to re-drawn itself. Try with BeginInvoke(), the asynchronous version (which also works when the thread is actually the same thread where the code is executed).
– Jimi
Nov 22 at 13:50
Control.Invoke() in synchronous. If it doesn't raise an exception, then the request has been fulfilled and the control's property has been updated. It doesn't mean that the UI had the chance to re-drawn itself. Try with BeginInvoke(), the asynchronous version (which also works when the thread is actually the same thread where the code is executed).
– Jimi
Nov 22 at 13:50
I am running a bunch of other operations for connecting to a COM Port and pushing commands down the pipe. So my aim was to show progress of everything as its doing all that. Seemed to have failed doing the easy way..
– William
Nov 22 at 15:00
I am running a bunch of other operations for connecting to a COM Port and pushing commands down the pipe. So my aim was to show progress of everything as its doing all that. Seemed to have failed doing the easy way..
– William
Nov 22 at 15:00
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
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accepted
I didnt want to do the long way but i guess i needed it done!
Basically the fix is below, i have added the ability to provide controls so its dynamic to everything but for the sake of this question, i will provide it for textbox.
Private Delegate Sub ResponseUpdateEventHandler(ByVal message As String)
Private Sub UpdateResponseBox(ByVal message As String)
If Txt_Response.InvokeRequired Then
Txt_Response.Invoke(New ResponseUpdateEventHandler(AddressOf UpdateResponseBox), New Object() {message})
Else
Txt_Response.AppendText(message + Environment.NewLine)
End If
End Sub
Then just call using: UpdateResponseBox("Connecting to device, Please wait...")
answered Nov 22 at 15:02
William
72
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
I didnt want to do the long way but i guess i needed it done!
Basically the fix is below, i have added the ability to provide controls so its dynamic to everything but for the sake of this question, i will provide it for textbox.
Private Delegate Sub ResponseUpdateEventHandler(ByVal message As String)
Private Sub UpdateResponseBox(ByVal message As String)
If Txt_Response.InvokeRequired Then
Txt_Response.Invoke(New ResponseUpdateEventHandler(AddressOf UpdateResponseBox), New Object() {message})
Else
Txt_Response.AppendText(message + Environment.NewLine)
End If
End Sub
Then just call using: UpdateResponseBox("Connecting to device, Please wait...")
answered Nov 22 at 15:02
William
72
add a comment |
up vote
0
down vote
accepted
I didnt want to do the long way but i guess i needed it done!
Basically the fix is below, i have added the ability to provide controls so its dynamic to everything but for the sake of this question, i will provide it for textbox.
Private Delegate Sub ResponseUpdateEventHandler(ByVal message As String)
Private Sub UpdateResponseBox(ByVal message As String)
If Txt_Response.InvokeRequired Then
Txt_Response.Invoke(New ResponseUpdateEventHandler(AddressOf UpdateResponseBox), New Object() {message})
Else
Txt_Response.AppendText(message + Environment.NewLine)
End If
End Sub
Then just call using: UpdateResponseBox("Connecting to device, Please wait...")
answered Nov 22 at 15:02
William
72
add a comment |
up vote
0
down vote
accepted
up vote
0
down vote
accepted
I didnt want to do the long way but i guess i needed it done!
Basically the fix is below, i have added the ability to provide controls so its dynamic to everything but for the sake of this question, i will provide it for textbox.
Private Delegate Sub ResponseUpdateEventHandler(ByVal message As String)
Private Sub UpdateResponseBox(ByVal message As String)
If Txt_Response.InvokeRequired Then
Txt_Response.Invoke(New ResponseUpdateEventHandler(AddressOf UpdateResponseBox), New Object() {message})
Else
Txt_Response.AppendText(message + Environment.NewLine)
End If
End Sub
Then just call using: UpdateResponseBox("Connecting to device, Please wait...")
answered Nov 22 at 15:02
William
72
I didnt want to do the long way but i guess i needed it done!
Basically the fix is below, i have added the ability to provide controls so its dynamic to everything but for the sake of this question, i will provide it for textbox.
Private Delegate Sub ResponseUpdateEventHandler(ByVal message As String)
Private Sub UpdateResponseBox(ByVal message As String)
If Txt_Response.InvokeRequired Then
Txt_Response.Invoke(New ResponseUpdateEventHandler(AddressOf UpdateResponseBox), New Object() {message})
Else
Txt_Response.AppendText(message + Environment.NewLine)
End If
End Sub
Then just call using: UpdateResponseBox("Connecting to device, Please wait...")
answered Nov 22 at 15:02
William
72
answered Nov 22 at 15:02
William
72
answered Nov 22 at 15:02
William
72
answered Nov 22 at 15:02
William
72
72
add a comment |
add a comment |
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I'm not seeing that behaviour. In my test, both controls reflected the change when it was made. I just had a
Thread.Sleepcall before and after the invocations. What else are you doing?– jmcilhinney
Nov 22 at 11:31
Control.Invoke() in synchronous. If it doesn't raise an exception, then the request has been fulfilled and the control's property has been updated. It doesn't mean that the UI had the chance to re-drawn itself. Try with BeginInvoke(), the asynchronous version (which also works when the thread is actually the same thread where the code is executed).
– Jimi
Nov 22 at 13:50
I am running a bunch of other operations for connecting to a COM Port and pushing commands down the pipe. So my aim was to show progress of everything as its doing all that. Seemed to have failed doing the easy way..
– William
Nov 22 at 15:00